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Airida
1 month ago
13

The function below takes a single string parameter: sentence. Complete the function to return a list of strings that are in the

sentence that contain a lowercase letter 'a'. Hint: you may find the split method and in operator useful in solving this problem.

Computers and Technology
1 answer:
Rzqust [894]1 month ago
4 0

Response:

#section 1

def listofWordswitha(text):

   ''' This function outputs all words from a string that include the letter 'a' '''

   tex = text.split()

   new = []

#section 2

   for word in tex:

       for char in word:

           if char == 'a':

               new.append(word)

               

               break

   return new

Clarification:

#section 1

First, you need to establish your function and provide an argument representing the string that will be utilized.

It's beneficial to include a docstring that describes the function's purpose, which I've added.

Then, use the split method to break the string into a list. In conclusion, you create a list to store all the words that contain 'a'.

#section 2

The terminology chosen is specific to facilitate understanding.

FOR EVERY WORD inside the list and FOR EACH LETTER in the WORD.

IF a LETTER 'a' is found in the word, ADD that WORD to the NEW LIST.

The append function serves to incorporate new entries into the list.

A break statement is employed to avoid redundancy since some words might have multiple instances of 'a'. Thus, upon encountering a word containing 'a', it appends it and shifts to the next word.

Ultimately, the new list is returned.

I will utilize your inquiry to validate the code and provide the results for you.

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Answer:

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//The Solution class is being defined

public class Solution {

   //The main method is declared here, marking the start of program execution

   public static void main(String args[]) {

       

       //A Scanner object named 'scan' is instantiated to gather user input

       Scanner scan = new Scanner(System.in);

       //User is prompted to specify the size of the array

       System.out.print("Enter the range of array: ");

       //The user input is stored in arraySize

       int arraySize = scan.nextInt();

       //Initialization of userArray with the size specified by arraySize

       int[] userArray = new int[arraySize];

       

       //A counter is initialized to track the number of elements entered in the array

       int count = 0;

       //The following while loop will continue until the user finishes inputting the elements of the array

       while (count < arraySize){

           System.out.print("Enter each element of the array: ");

           userArray[count] = scan.nextInt();

           count++;

       }

       

       //A blank line is outputted for better readability

       System.out.println();

       

       //A for loop iterates to print all elements of the array in a single line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

       

       //Another blank line is printed for clarity

       System.out.println();

       

       //A for loop is utilized to reverse the contents of the array

       for(int i=0; i<userArray.length/2; i++){

           int temp = userArray[i];

           userArray[i] = userArray[userArray.length -i -1];

           userArray[userArray.length -i -1] = temp;

       }

       

       //A for loop prints each element of the reversed array in one line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

     

   }

}

Explanation:

The program is annotated to provide a thorough explanation.

The for-loop responsible for reversing the array operates by splitting the array into two segments and swapping elements from the first segment with those from the second segment. During each loop, an element from the first segment is temporarily stored in temp variable, and then that element is replaced with the corresponding element from the second segment. Subsequently, the element from the second segment is updated with the value held in temp.

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A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen
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Answer:

C3H8

Explanation:

Step 1:

Relevant details from the question are noted below:

Mass of the alkane is 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Convert to the appropriate units.

For Volume:

1000mL = 1L

So, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature in Kelvin = Temperature in Celsius + 273

Temperature in Celsius = 28°C

Temperature in Kelvin = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

So, 741 mmHg = 741/760 = 0.975atm

Step 3:

Calculate the moles of the alkane.

The moles of the alkane can be found using the ideal gas equation, presented below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of moles (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 moles

Step 4:

Calculate the alkane’s molar mass.

Mass of alkane = 1.17g

Number of moles = 0.0266moles

Molar Mass =?

Number of moles = Mass/Molar Mass

Molar Mass = Mass/Number of moles

Molar Mass of alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determine the molecular formula of the alkane.

This is based on:

The general formula for alkanes is CnH2n+2

To find the molecular formula, we start with n = 1, 2, 3, etc., until we find the molar mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

It can be observed that for n equal to 3, the molar mass is 44g/mol.

Thus, the molecular formula of the alkane is C3H8.

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