Response: 1,500,000 bytes.
Clarification:
If we assume the image dimensions are 4000 pixels in width and 3000 pixels in height, the total uncompressed image will consist of 4000*3000= 12,000,000 pixels.
In the case of a binary image, each pixel can have only two values, which necessitates one bit for each pixel.
This indicates that we need to accommodate 12,000,000 bits.
Given that 1 byte equals 8 bits.
So, to store an uncompressed binary image sized 4000 x 3000 pixels, 12,000,000/8 bytes is required ⇒ 1,500,000 bytes.
<span>Port 80 is being blocked by the Windows Firewall.</span>
He should pursue a bachelor's degree next. I am also taking the test and choosing option A.
1/.0000667 = 14,992.5;
18,000,000/14,992 = 1,200 subcarriers
For an 18 Mbps LTE data stream utilizing a symbol duration of 66.67 μs, 1,200 subcarriers are generated.
