There are 0.015 kilograms in 15 grams. Since each can weighs 0.015 kg and the payment rate is 50p per kilogram, 0.015 multiplied by 66 amounts to 1 kilogram! Therefore, 66 cans are needed to generate one kilogram. As a result, earning £15 would mean that with 2 kg equating to one dollar, then 15 multiplied by 2 equals 30. Consequently, 66 times 30 gives 1980!
66 relates to each kilogram, and 30 indicates how many 50p are required for one dollar!
Thus, to obtain £15, Adam has to recycle a total of 1980 cans!
Response:
- Refer to the attached graph
Clarification:
To analyze log (−5.6x + 1.3) = −1 − x visually, graph these equations on the same coordinate system:
- Equation 1: y = log (5.6x + 1.3)
The first equation can be graphed using these characteristics of logarithmic functions:
- Domain: values must be positive ⇒ -5.6x + 1.3 > 0 ⇒ x < 13/56 (≈ 0.23)
- Range: all real values (- ∞, ∞)
log ( -5.6x + 1.3) = 0 ⇒ -5.6x + 1.3 = 1 ⇒ x = 0.3/5.6 ≈ 0.054
x = 0 ⇒ log (0 + 1.3) = log (1.3) ≈ 0.11
- Choose additional values to create a table:
x log (-5.6x + 1.3)
-1 0.8
-2 1.1
-3 1.3
- This graph is shown in the attached image: it's represented by the red curve.
Graphing the second equation is simpler as it forms a straight line: y = - 1 - x
- slope, m = - 1 (the coefficient of x)
- y-intercept, b = - 1 (the constant term)
- x-intercept: y = 0 = - 1 - x ⇒ x = - 1
- This graph is indicated by the blue line in the image.
The resolution to the equations corresponds to the points where the two graphs intersect. The graphing method thus allows you to determine the x coordinates of these intersection points. Ordered from smallest to largest, rounded to the nearest tenth, we have:
Answer: the factored form is (4x+8)(x-9)
Step-by-step explanation:
Answer:
The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction
Step-by-step explanation:
In order to simplify the expression
where x ≠ 0, y ≠ 0, we must work through the given expression.

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction