A board 120 inches long is divided into 2 sections. If the ratio of the 2 sections is 3:5, what are the lengths of the sections?

Answer: The correct choice is (C) A = {1, 2, 3, 4, 5, 7, 8}.

Step-by-step explanation: We have eight identical slips of paper, each numbered from one to eight, which have been mixed inside a bag.

The sample space, S is as follows:

S = {1, 2, 3, 4, 5, 6, 7, 8}.

Subset A consists of the complement of the event where the number 6 is drawn.

Let 'B' denote the event of drawing the number 6.

Thus, B = {6}.

Since 'A' represents the complement of 'B', it will include all elements in the sample space 'S' that are not part of set 'B'.

Therefore,

A = B' = {1, 2, 3, 4, 5, 7, 8}

So, A = {1, 2, 3, 4, 5, 7, 8}.

Consequently, (C) is the correct choice.

Quadratic equations find their application in various real-world scenarios such as: sports, bridges, projectile motion, the curvature of bananas, and so on.

Here are three images representing real-world instances of quadratics:

Example 1: A cyclist travels along a parabolic trajectory to leap over obstacles.

Example 2: A person throws a basketball towards the hoop, moving in a gently upward path described by a quadratic curve.

Example 3: A football player kicks the ball upward, which follows a quadratic path as it travels a distance.

The likelihood of selecting one girl is calculated as . This is based on having 5 girls within a total of 12 students, and the probability of an event can be expressed as: .

Using the same reasoning, for the next student, we have reduced the number of students by 1, leading to 11 possible outcomes instead of 12, giving us:, which represents the probability of selecting a boy as the second choice.

Lastly, the probability of choosing a girl for the third selection follows the same logic and is given as:.

However, we must combine these individual probabilities to determine the likelihood of this specific sequence of selections occurring:

This simplifies to: