<span>This is quite challenging, but here’s the solution:
</span>
y = x^2 - 10x + 25 - 25
<span> y = (x-5)^2 - 25</span>
<span> y + 25 = (x-5)^2</span>
<span> x - 5 = ±sqrt(y+25)</span>
<span> You will derive TWO inverses:</span>
<span> x = 5 + sqrt(y+25),</span> for x ≥ 5
<span> x = 5 - sqrt(y+25),</span> for x ≤ 5
The question appears to be incomplete. Here’s the complete inquiry:
Samir is quite skilled with the gun. When he targets a specific aim at the shooting range, he has a 0.95 probability of striking it. On one occasion, Samir sets out to shoot 10 targets consecutively.
If he has the same chance of hitting each of the 10 targets, what is the likelihood that he will miss at least one?
Response:
40.13%
Step-by-step breakdown:
Let 'A' represent the event of successfully hitting all targets in 10 trials.
The complement of 'A' is 
Now, since Samir has a consistent probability of hitting each target at 0.95.
Now, 
We know that the combined probability of an event and its complement equals 1.
<pThus,

Consequently, the probability that he misses at least one target among 10 attempts is 40.13%.
Details provided:
Confidence level = 90%
Mean = 71 beats per minute
Standard deviation = 6 beats per minute
The formula for margin of error is z * δ / √n.
Where δ represents the population standard deviation and n is the sample size; z denotes the corresponding z-value.
For a 90% confidence level, the z-value is 1.645.
Thus, the margin of error is calculated as 1.645 * (6/√80) = 1.645 * (6/8.94) = 1.645 * 0.671 = 1.104.
Answer:
The detailed work and solution can be found in the attachment
Step-by-step explanation:
Answer:
Step-by-step explanation:
For question 1, the result is calculated by dividing the percentage of students in the sports club by the SAT average, while for question 2, the answer is no since the definitions yield contrary outcomes.