Answer:
According to my cupcake recipe, it yields $12$ cupcakes and calls for $1\frac{1}{2}$ sticks of butter. I can only purchase whole sticks of butter.
Consequently, a single whole stick of butter will suffice to prepare $100$ cupcakes.
Answer:
x = 11.33 years
Step-by-step explanation:
The equation for rainbow smelt is Y1 = −19.76x + 227
For bloater fish, the equation is Y2 = –92.57x + 1052
To find where these populations are equal:
–19.76x + 227 = –92.57x + 1052
Combine like terms:
-19.76x + 92.57x = 1052 - 227
72.81x = 825
Now divide by 72.81:
x = 825 / 72.81
Thus,
x = 11.33 years
Pr(X>1540.2) = 0.0655. Step-by-step explanation: The expected value indicated for the large bottle is E(Large) = 1016, and for the small bottle, E(small) = 510. This leads to an expected total E(total) = 1016 + 510 = 1526. The new mean calculated is thus 1526. To find the standard deviation, we derive the variance of each bottle. The variance for the large bottle is v(large) = 8^2 = 64, while for the small bottle it's v(small) = 5^2 = 25. Hence, the total variance is v(total) = 64+25 = 89, resulting in a new standard deviation sd(new) = sqrt(89) = 9.434. To find the probability, we compute using the new mean and standard deviation. The z score is derived as z = (x - mean)/sd = (1540.2 - 1526)/9.434 = 1.505. Looking up this z score gives P(z<1.51) = 0.9345. Consequently, for x > 1540.2, we have P(z > 1.51) = 1 - 0.9345 = 0.0655.
Response:
The answer is 1/13
To explain step-by-step:
We are notinformed about the first (01) twelve (12) cards that are shown; hence, the probability that the thirteenth (13) card dealt is a King is equivalent to the probability of the first card being a King, or specifically any designated card dealt being a King, equating to:
=4/52
=
1/13 FINAL RESULT
The maximum number of plates Lenin can create is 4, with each plate containing 3 pieces of chicken and 4 rolls. Step-by-step explanation: Lenin is preparing dinner plates with 12 pieces of chicken and 16 rolls. To ensure all plates are identical without any leftover food, the greatest number of plates he can prepare is represented by the G.C.D.(12,16) = 4. Each plate will therefore include 3 pieces of chicken and 4 rolls.
