Anna draws an angle in her notebook. in how many points do the rays intersect?

Step-by-step explanation:

The equation for the best fitting line is y = 2.599x + 105.08. When x is set to 20, the predicted height becomes y = 157.06. However, the actual height recorded is 160 cm, therefore, the residual is calculated as:

160 cm − 157.06 cm = 2.94 cm

Answer:

The upper limit for the height of the prism is

Step-by-step explanation:

Let

x------> represent the height of the prism

It is known that

the area of the base of the prism must not exceed

thus

-------> inequality A

------> equation B

-----> equation C

Insert equation B into equation C

------> equation D

Substituting equations B and D into inequality A

-------> using a graphing tool to solve the inequality

The resultant solution for x lies in the interval---------->

consult the attached figure

but bear in mind that

The width of the base must be meters shorter than the height of the prism

thus

the solution for x is confined to the interval ------>

The maximum height of the prism equals

Answer: To remove fractions prior to solving, each term in the equation must be multiplied by .

Step-by-step explanation:

Consider the given expression:

It is essential to simplify this before attempting to solve it.

Since the denominators differ, identifying the Least Common Denominator (LCD) is necessary.

Break down the denominators into their prime components:

Select , as it possesses the greatest exponent. Thus:

Ultimately, to remove the fractions before solving, multiply both sides by 4:

Answer:

E(t) = [ 4cos(t), 2 sin(t) ]

Step-by-step explanation:

The equation for the ellipse can be represented as:

 (x² ÷ a² ) + (y² ÷ b² ) = 1    Here, a and b symbolize the semi-major and semi-minor axes.

In this specific instance, we have    x²/16 + y²/ 4 = 1

This expression indicates that it follows the form of (x/a)² + (y/b)² =1

Specifically in our case,    x²/16  + y²/4 = 1, which resembles                 sin²α + cos²α = 1.

By setting x = 4 cos(t), we can proceed to calculate y.

Utilizing the equation x²/16  + y²/4 = 1, we find that:

x²/16  + y²/4 = 1   ⇒    (x²  +  4y²) ÷ 16  = 1

Solving for y yields: (x²  +  4y²)  = 16    ⇒  y²  = ( 16 - x²) ÷4

Substituting x = 4 cos(t) gives us y²  =  (16 - 16cos²(t)) ÷ 4, leading to y = √4 (1 - cos²(t)).

Consequently, we have y = 2 sin(t).

Thus, the vector parameterization of the ellipse can be stated as:

E(t) = [ 4cos(t), 2 sin(t) ]