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kakasveta
11 days ago
11

PLEASE HELPPP!! Triangle HJK and triangle PMK are similar right triangles.

Mathematics
2 answers:
babunello [11.2K]11 days ago
7 0
The answer must be B Step-by-step explanation:
Leona [12K]11 days ago
3 0
The answer is B:) Step-by-step explanation:
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0.002 is 1/100 of what decimal?
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The appropriate conversion should be 0.2. If that's incorrect, please let me know.
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Which graph represents the function f(x) = (x – 5)2 + 3?
Inessa [12071]
The function
f(x)=(x-5)^2+3
represents a parabola positioned at the vertex (5, 3).

Attached here is the graph depicting this function.

4 0
1 month ago
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If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK
lawyer [12053]

Response:

The measure of mHLK is "(204)°".

Step-by-step breakdown:

Given values include:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

What is mHLK?

Now,

Utilizing the chord-chord angle formula, we find

mHMK=\frac{1}{2}(mJL+mHLK)

Inserting the known values into the equation gives us

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

By carrying out cross-multiplication, we arrive at

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

By subtracting "18x" from both sides, we obtain

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

Upon adding "2" to both sides, we end up with

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

By substituting the value of "x" into mHLK = (15x-36)°, we calculate

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

Thus, mHLK = (204)°

4 0
1 month ago
During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16
Inessa [12071]

Answer:

2.5 seconds after the initial ball was struck.

Step-by-step explanation:

The height equations are:

  • h = -16t² + 56t
  • h = -16t² + 156t - 248

At the point where the balls intersect, both heights are alike, therefore:

-16t² + 56t = -16t² + 156t - 248

-16t² + 56t + 16t² - 156t + 248 = 0

- 100t + 248 = 0

248 = 100t

t = 248/100

t = 2.48 ≈ 2.5

4 0
1 month ago
Given: AD ≅ BC and AD ∥ BC Prove: ABCD is a parallelogram. Statements Reasons 1. AD ≅ BC; AD ∥ BC 1. given 2. ∠CAD and ∠ACB are
tester [11824]

Given: AD ≅ BC and AD ∥ BC

Prove: ABCD is a parallelogram.

Statements                                                                 Reasons

 1. AD ≅ BC; AD ∥ BC                                                1. provided

 2. ∠CAD and ∠ACB are alternate interior angles        2. definition of alternate interior angles

3. ∠CAD ≅ ∠ACB                                                    3. congruence of alternate interior angles

4. AC ≅ AC                                                              4. reflexive property

 5. △CAD ≅ △ACB                                                  5. SAS congruency theorem

6. AB ≅ CD                                                            6. Congruent triangles have congruent corresponding parts (CPCTC)

7. ABCD is a parallelogram                                  7. theorem for sides of parallelograms

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