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Nikolay
3 months ago
7

jane lives 1 3/8 miles from the airport. She drove from her house to the airport and back 2 times. How far did Jane drive? Move

a number or numbers into the blank to show the answer
Mathematics
1 answer:
Leona [12.6K]3 months ago
4 0

Response:

5\frac{1}{2}\ mi

Detailed explanation:

We are aware that

1\frac{3}{8}\ mi=\frac{1*8+3}{8}=\frac{11}{8}\ mi

She made the trip between her residence and the airport twice.

Therefore,

Multiply the distance from her house to the airport by 4.

(4)*\frac{11}{8}=\frac{11}{2}=5\frac{1}{2}\ mi

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Find three solutions for the linear equation 4x −3y = 1, and plot the solutions as points on a coordinate plane.
lawyer [12517]

Answer:

(1, 1), (2, 2.333) and (3, 3.666).

Step-by-step explanation:

To solve this equation, we can select various values for x and then compute the corresponding y values.

<pFor instance, when x = 1, we find:

4*1 - 3y = 1

3y = 3

y = 1

When x = 2, we discover:

4*2 - 3y = 1

3y = 7

y = 2.333

Then for x = 3, we have:

4*3 - 3y = 1

3y = 11

y = 3.666

Therefore, the coordinates we will plot are (1, 1), (2, 2.333), and (3, 3.666).

Refer to the attached image for the plot.

4 0
3 months ago
Eliot was trying to factor 6x^2-18. He found that the greatest common factor of these terms was 6 and made an area model
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Have you discovered the solution yet? I'm a bit stuck.
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2 months ago
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At first, Kai earned a score of 80 on a quiz. He discovered that 5 points had been taken
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The initial score was 80, and there was a wrongfully deducted 5 points. This indicates that any result equating to 85 is the correct outcome.

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You are given a list of students names and their test scores. Design a pseudocode that does the following:(a) Calculates the ave
Zina [12379]

Answer:

List_of_students = {};    //Array structure that holds student scores and names

Number_of_students = size(List_of_students);

Average_score;   //Variable to keep the average score

Below_Average = [];   //Initially filled with zeroes  

Highest_score; //Variable initialized to store the highest score

for ( i = 0; i < Number_of_students; i = i + 1)

{

     Average_score  = Average_score + List_of_students(i);    

     if ( i = 15)

     {

        Average_score  = Average_score / Number_of_students;

     }

}

for ( j = 0; j < Number_of_students; i = i + 1)

{

     if (List_of_students(j) < Average_score)

     {

         print( "student  %name scored %score, List_of_students(j),          List_of_students(j) )

     }

}

Compare_Score = 0;   //Variable for score comparison

for ( k = 0; K < Number_of_students; k = k+1)

{

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    }

}

Highest_Score = Compare_Score;

Step-by-step explanation:

4 0
2 months ago
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