There will still be 34.5 L of water in the two pails combined because no water is lost.
Thus the total remains 34.5 L after transferring water between them.
Let the final amount in the smaller pail be x.
Then the larger pail contains 9x.
So x + 9x = 34.5.
That simplifies to 10x = 34.5.
Dividing both sides by 10 gives x = 3.45.
Therefore the smaller pail held 3.45 L at the end.
Because 0.68 L was poured into it, its initial volume was 2.77 L (3.45 minus 0.68)
We can also deduce the larger pail initially contained 31.73 L
(either 35 minus 2.77, or 9 times 3.45 plus 0.68)
Answer:
£170,000
Step-by-step explanation:
En 2010, Rafik adquirió una casa. Supongamos que el precio de compra fue $x. En 2015, Rafik vendió la casa a Bianca obteniendo un 20% de ganancia. Esto se traduce en 20% de x lo que equivale a 0.2 × x = 0.2x. Por tanto, Rafik vendió la casa a Bianca por x + 0.2x = 1.2x. Bianca compró la casa a 1.2x.
La casa fue vendida por Bianca en 2019 con una pérdida del 5%. Esto implica que el 5% de pérdida equivale a 0.05(1.2x) = 0.06x.
Por consiguiente, la venta de la casa por Bianca se realizó a 1.2x - 0.06x = 1.14x. Dado que la casa se vendió por £193,800.
⇒ 1.14x = 193,800
x = 193,800/1.14
x = £170,000
Rafik pagó £170,000 por la casa en 2010.
<span>m=10x-x for x
begin by taking x away from 10x
m=9x
then divide each side by 9
m/9=x
therefore, x=m/9</span>
To derive the function that characterizes the bee population:
1) Initially, there are 9,000 bees in the first year.
2) In the second year, a reduction of 5% occurs => 9,000 - 0.05 * 9,000 = 9,000 * (1 - 0.05) = 9,000 * 0.95
3) Each subsequent year sees a 5% decline => 9,000 * (0.95)^(number of years)
4) Let x represent years and f(x) signify the bee count, then: f(x) = 9,000 (0.95)^x.
Evaluation of the claims:
<span>1) The function f(x) = 9,000(1.05)x applies to the scenario.
FALSE: WE ESTABLISHED IT AS f(x) = 9,000 (0.95)^x
2) The function f(x) = 9,000(0.95)x applies to the scenario.
TRUE: THIS IS THE RESULT OF OUR PRIOR ANALYSIS.
3) After 2 years, the farmer projects approximately 8,120 bees will be left.
Calculating:
f(2) = 9,000 * (0.95)^2 = 9,000 * 0.9025 = 8,122
Thus, this statement is TRUE
4) After 4 years, the farmer can predict there will be roughly 1,800 bees left.
f(4) = 9,000 * (0.95)^4 = 9,000 * 0.81450625 = 7,330
This statement is therefore FALSE
5) The domain values contextual to this situation are restricted to whole numbers.
FALSE: DOMAIN VALUES INCLUDE ALL NON-NEGATIVE REAL NUMBERS. FOR INSTANCE, THE FUNCTION IS VALID AT X = 5.5
6) The range values pertinent to this situation are restricted to whole numbers.
TRUE: FRACTIONS OF BEES CANNOT EXIST.
</span>
Answer:
0.93 minute
Step-by-step explanation:
During the first week:
Kim ran = 1 mile
Duration for this distance = 1 minute
In the second week:
The distance covered by Kim = 1 mile
The time taken by Kim = 7% less compared to the first week
= 1 min - 0.07 min = 0.93 minute
<pSo, she completed 1 mile in 0.93 minute this week.
