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SIZIF
5 days ago
7

two pairs of different sizes contain 34.5 liters of water altogether. when 0.68 liter of water is poured from the bigger pail in

to the smaller pail, the amount of water in the bigger pail is 9 times that in the smaller pail. how much water was there in each pail at first?
Mathematics
1 answer:
zzz [11.8K]5 days ago
6 0
There will still be 34.5 L of water in the two pails combined because no water is lost.
Thus the total remains 34.5 L after transferring water between them.
Let the final amount in the smaller pail be x.
Then the larger pail contains 9x.
So x + 9x = 34.5.
That simplifies to 10x = 34.5.
Dividing both sides by 10 gives x = 3.45.
Therefore the smaller pail held 3.45 L at the end.
Because 0.68 L was poured into it, its initial volume was 2.77 L (3.45 minus 0.68)
We can also deduce the larger pail initially contained 31.73 L
(either 35 minus 2.77, or 9 times 3.45 plus 0.68)
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