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1 month ago

6

A greengrocer sells a melon at a profit of 37.5% on the price he pays for it. what is the ratio the cost price to the selling pr

ice?

1 answer:

tester [12.3K]1 month ago

4 0

$\frac{100}{137.5} = \frac{1}{1.375}$ I divided by 100 and shifted the decimal point two places left.

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Angela makes a pillow in the shape of a wedge to use for watching TV. The pillow is filled with 0.35 m3 of fluffy

Svet_ta [12734]

Complete Question

Angela has constructed a wedge-shaped pillow for her TV watching needs. It contains 0.35 m³ of fluffy material. The pillow's base area measures 0.5m², and its height stands at 1m.

What is the length of the pillow?

Provide an exact answer (no rounding).

Answer:

1.4m

Step-by-step explanation:

A wedge can be defined as a Triangular prism. Thus,

The volume formula for a wedge (Triangular prism) is given by: 1/2 × B × H × L

b = 0.5m

h = 1 m

l =??

Volume of the wedge = 0.35 m³

0.35 = 1/2 × 0.5 × 1 × L

0.35 = 0.25 × L

Solving for L, we get: L = 0.35/0.25

L = 1.4m

4 0

1 month ago

There are 200 students in the 7th grade class at Brookside Middle School. Of these students, 12% play volleyball and 15% play ba

Svet_ta [12734]

P(volleyball and baseball) = 4/200 x 100 = 2%
P(volleyball or baseball) = P(volleyball ∪ baseball) = P(volleyball) + P(baseball) - P(volleyball and baseball) = 12% + 15% - 2% = 25%.

Thus, 25% of students participate in either volleyball or baseball.

4 0

26 days ago

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Marcy has $150 to buy packages of hot dogs and hamburgers for her booth at the carnival. At her local grocery store she found pa

lawyer [12517]

6d + 20b = 150 d=5 b=6

5 0

22 days ago

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The idle time for taxi drivers in a day are normally distributed with an unknown population mean and standard deviation. If a ra

Svet_ta [12734]

Answer:

$172-2.51\frac{16}{\sqrt{23}}=163.626$

$172+2.51\frac{16}{\sqrt{23}}=180.374$

Hence, in this case, the 98% confidence interval would be (163.626;180.374)

Step-by-step breakdown:

Previous concepts

A confidence interval represents a range that is likely to encompass a population value within a specific confidence level, typically expressed as a percentage whereby a population mean falls between an upper and lower limit.

The margin of errorindicates the span of values surrounding the sample statistic in a confidence interval.

A normal distributionillustrates a probability distribution that is symmetrical around the mean, signifying that values near the mean occur more frequently than those farther away from it.

$\bar X=172$ denote the sample mean

$\mu$ population mean (the variable of interest)

s=16 signifies the sample standard deviation

n=23 represents the sample size

The solution to the query

The equation for the confidence interval of the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

To determine the critical value $t_{\alpha/2}$ , we first need to calculate the degrees of freedom, which is expressed as:

$df=n-1=23-1=22$

Since the confidence level is 0.98 or 98%, we find the value of $\alpha=0.02$ and $\alpha/2 =0.01$ using tools like Excel or a calculator, where the Excel command would be: "=-T.INV(0.01,22)". This yields $t_{\alpha/2}=2.51$

Having all components ready, we can substitute into formula (1):

$172-2.51\frac{16}{\sqrt{23}}=163.626$

$172+2.51\frac{16}{\sqrt{23}}=180.374$

Thus, for this case, the 98% confidence interval will be (163.626;180.374)

3 0

14 days ago

Segment JK has a length of 4.5 units. If segment LM has end points of L (3,1) and M (-1,4), how much longer than segment JK is s

Leona [12618]

Distance formula:
$d= \sqrt{ (x_{2}-x_{1}) ^{2}+( y_{2} - y_{1} )^{2}}\\ d= \sqrt{ (3-(-1)) ^{2}+(1 - 4 )^{2}}\\ d= \sqrt{ (4) ^{2}+(-3)^{2}}\\ d=\sqrt{16+9}\\ d=\sqrt{25}\\ d=5$

5 units-4.5 units=0.5 units

Segment LM exceeds segment JK by 0.5 units.

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1 month ago

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