Answer:
This is how the money should be divided:
Each of my two younger siblings receives P3,000.
I will take P4,000.
The reasoning for this allocation stems from the principle that the eldest and youngest siblings should not receive equal portions when dividing assets.
Step-by-step explanation:
This division approach is the only sensible method to distribute P10,000 among myself and my younger siblings while ensuring no fractions are involved, maintaining whole peso amounts. Any other method would result in leftover change.
Answer:
C. 4x^3 - 14x^2y + 14xy^2 - 4y^3
Step-by-step explanation:
Given:
Multiplication of 2x^2 – 3xy + y^2 and 2x – 4y
Multiplication refers to the product
(2x^2 – 3xy + y^2) (2x – 4y)
Expand the brackets
= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3
Combine like terms
= 4x^3 - 14x^2y + 14xy^2 - 4y^3
The result is
C. 4x^3 - 14x^2y + 14xy^2 - 4y^3
No.
In order to conduct an analysis like this one, it is essential to select a RANDOM SAMPLE from the entire POPULATION involved in the study. For instance, Pete is attempting to gauge the overall satisfaction of his customers, therefore, he should distribute the surveys to a randomly chosen group of customers rather than only targeting those who have bought the most items. Doing so will yield results that are more REPRESENTATIVE of the overall customer satisfaction. If he limits the surveys to those customers who have purchased the most, he is likely to see inflated satisfaction levels, which would not truly reflect the general sentiment of all customers.
Answer:
It could either be 455 or 680, based on assumptions.
Step-by-step explanation:
Assuming the three choices are distinct, we can calculate...
15C3 = 15·14·13/(3·2·1) = 35·13 = 455
ways to create the pizza.
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In the case where two or more of the toppings may be identical, this would lead to...
2(15C2) + 15C1 = 2·105 + 15 = 225
additional combinations, resulting in a grand total of...
455 + 225 = 680
unique pizza varieties.
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There is a multiplication factor of 2 for the two-topping selections, since it allows for variations like double anchovies and tomatoes or double tomatoes and anchovies when the topping choices are anchovies and tomatoes.
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nCk = n!/(k!(n-k)!)
