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IceJOKER
7 days ago
12

Leslie was able to map \overline{ST} ST start overline, S, T, end overline onto \overline{QR} QR ​ start overline, Q, R, end ove

rline using a rotation and dilation. Leslie concluded: "I was able to map \overline{ST} ST start overline, S, T, end overline onto \overline{QR} QR ​ start overline, Q, R, end overline using a sequence of rigid transformations, so the figures are congruent." What error did Leslie make in her conclusion?
Mathematics
2 answers:
zzz [12.3K]7 days ago
3 0
Leslie's mistake lies in using a dilation, which either scales an object down or up. This transformation cannot be applied because congruent segments must maintain equal length; only rigid transformations like translations, reflections, and rotations are permissible. Thus, dilation is not considered a rigid transformation.
lawyer [12.5K]7 days ago
3 0
I completed the task on Khan Academy.
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Emilia saved nickels, dimes, and quarters in a jar. She had as many quarters as dimes, but twice as many nickels as dimes. If th
tester [12383]

Let’s define the number of nickels as n,

the number of dimes as d, and

the number of quarters as q.

The total quantity of coins is 844.

We can express this as "number of nickels + number of dimes + number of quarters = Total coins.

Thus, we can form an equation from this statement as

n+d+q = 844            ---------------------equation(1).

Additionally, it is given that Emilia possesses as many quarters as dimes.

Consequently, the number of quarters equals the number of dimes.

This leads to another equation:

q = d                          ------------------------equation(2).

It is also stated that there are "twice as many nickels as dimes."

We can create a further equation representing this statement as

n = two times the number of dimes

or n= 2d                -------------------------- equation (3).

Three equations have been established.

Let’s solve this system of three equations using substitution methods.

By substituting q = d and  n= 2d  into equation (1), we obtain

n+d+q = 844      =>

2d +d + d = 844.

Adding up the d's, gives us

4d =844.

Dividing both sides by 4 yields

\frac{4d}{4}=\frac{844}{4}

d = 211.

Hence, the quantity of dimes = 211.

Next, we will determine the number of nickels and quarters.

We know that the number of quarters equals the number of dimes.

Thus, the total count of quarters is 211.

The overall quantity of coins sums to 844.

Hence, the number of nickels = 844 -  (sum of quarters and dimes).= 844 -(211+211) = 844 - 422

= 422.

Therefore,

the total of nickels = 422.

Now, let’s compute the total values of all coins.

A nickel is valued at $0.05

A dime is valued at $0.10

A quarter is valued at $0.25.

The total value = 0.05 *(number of nickels) + 0.10*(number of dimes) + 0.25*(number of quarters).

=[ 0.05* 422 + 0.10 *211 + 0.25*211].

= 21.10 + 21.10 + 52.75.

= 94.95.

So, the total worth of all 844 coins = $94.95.

Emilia saved $94.95.

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10 days ago
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−4x+60<72 or 14x+11<−31 solve for x
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The answer to your question is x = 8
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1 month ago
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At smith mountain lake boat rentals, it costs $25 per hour to rent a pontoon boat, plus a one-time charge for cleaning. The Beng
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The equation provided in slope-intercept form is 226.50 = 7.5 (25) + 39. Step-by-step explanation: The slope-intercept form of an equation is represented by y = mx + c. The hourly cost of boat rental is $25. Assuming a one-time cleaning fee of k, and with the boat rented from 11 am to 6:30 pm, the total hours of use amount to 7.5 hours. Consequently, the rental cost for those 7.5 hours becomes 7.5 multiplied by $25, equating to $187.50. The total sum paid by the family amounts to $226.50, which equals the cleaning fee plus the 7.5-hour rate. Thus, the cleaning charge comes to $226.50 - $187.50 = $39. The equation presented reflects this relationship.
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The perimeter of a scalene triangle is 14.5 cm. The longest side is twice that of the shortest side. Which equation can be used
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Let x = 6.2
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A rectangle is transformed according to the rule R0, 90º. The image of the rectangle has vertices located at R'(–4, 4), S'(–4, 1
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We understand that a rectangle has been altered into the one shown in Figure 1 using this rule:

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The rule to convert a point in this case is:

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This rule has already been implemented to create the image, so we need to reverse the outcome using this formula, hence:

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2. Counterc
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Applying the same concept as before but with new rules for the scenario:

(x,y) \rightarrow (-y,x)

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3 0
10 days ago
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