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son4ous
1 month ago
12

The recipe makes enough stew for 6 people, and the ingredients cost $9.75. How much would it cost to serve 24 people? Use the ra

te table to solve the proportion.
Mathematics
3 answers:
Leona [12.6K]1 month ago
6 0
To calculate the cost for 24 people, you need to multiply both 6 and 9.75 by 4 because there are going to be 24 participants. Thus, 6 • 4 equals 24 and 9.75 • 4 equals 39!
lawyer [12.5K]1 month ago
6 0

Answer: The total cost of ingredients for a recipe serving 24 individuals is $39.

Step-by-step explanation: It's known that a recipe provides enough stew for 6 individuals and costs $9.75.

We aim to determine the cost of the ingredients needed for serving 24 individuals.

Using the rate table to solve the problem is essential.

<pGiven the increase in the number of people is a factor of

\dfrac{24}{6}=4.

Therefore, we will multiply the ingredient cost for 6 servings by 4.

The cost of ingredients for 24 individuals results in

=9.75\times 4\\\\=39.

Hence, the final cost of ingredients required to serve 24 is $39.

PIT_PIT [12.4K]1 month ago
0 0

In the second ratio, the number of people is mistakenly placed as the denominator. It should be the numerator to align with the first ratio.

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Solve x2 - 8x - 9 = 0. Rewrite the equation so that it is of the form x2 + bx = c.
Svet_ta [12734]

Answer:

x=9,-1 and x^2+(-8)x=9

Explanation:

We are given the quadratic equation x^2-8x-9

, which we then compare with the standard form of a quadratic. The general quadratic is identified as ax^2+bx+c=0

. From our given equation, it follows that a=1,b=-8,c=-9

. To calculate the discriminant, we insert these values into the formula D=b^{2}-4ac

D=(-8)^2-4(1)(-9)=100

. Now, to find the value of x

The formula is x=\frac{-b\pm\sqrt{D}}{2a}

. The resulting equation will be obtained by rewriting the original equation through rearranging 9 to the right side and applying negative signs within brackets to convert the expression into the form of

x^2+bx=c

.
4 0
1 month ago
Read 2 more answers
Yao Xin puts 3/10 liters of potting soil in each pot for planting flowers. She has 17/3 liters of potting soil. How many pots ca
babunello [11817]

In this scenario, we'll define the following variables:

x: total volume of potting soil in liters.

y: quantity of potting soil allocated to each pot in liters.

To determine the number of pots, we can use the expression:

N = \frac{x}{y}

Substituting in the respective values yields:

N = \frac{\frac{17}{3}}{\frac{3}{10}}

Reformatting gives us:

N = \frac{170}{9}

N = 18.8

When rounding down to the nearest whole number, we find:

N = 18

The conclusion is:

Yao Xin is capable of filling 18 pots.

4 0
1 month ago
Alejandro made an error in the steps below when determining the equation of the line that is perpendicular to the line 4x – 3y =
Svet_ta [12734]
The equation of the perpendicular line can be identified by determining its slope and applying the given point within the standard formula.

Standard equation: y-y1 = m(x-x1)

m*m'=-1
where m' indicates the slope of the perpendicular line
m denotes the slope of the original line

m = -coefficient of x/coefficient of y = -4/-3 = 4/3
m' = -3/4

Substituting the point (3, -2):
y+2 = -3/4*(x-3)
4y+8 = -3x+9

Thus, the equation of the perpendicular line is: 3x+4y-1=0
7 0
1 month ago
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Suppose A is a 5x7 matrix. How many pivot columns must A have if its columns span R^5​? ​Why?
babunello [11817]
The correct answer is "Option B." There seems to be an error with the options provided; however, the appropriate choice is detailed in the attached file. If the column of the matrix and the span of A are both equal to R^5, then A must have a pivot in each row, hence resulting in five pivot columns that confirm choice B as accurate.
4 0
1 month ago
Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. x2 + y2 = 25 (a) Fin
Zina [12379]

Answer:

(a) \frac{dy}{dt}=-3\frac{3}{4}

(b) \frac{dx}{dt}=3\frac{3}{4}

Step-by-step explanation:

x^{2} +y^{2}=25

Calculate \frac{d}{dt} for each term.

\frac{d}{dt}(x^{2})+\frac{d}{dt}(y^{2})=\frac{d}{dt}(25)\\\\(\frac{d}{dx}(x^{2})*\frac{dx}{dt}) +(\frac{d}{dy}(y^{2})*\frac{dy}{dt})=\frac{d}{dt}(25)\\\\2x\frac{dx}{dt} +2y\frac{dy}{dt} = 0\\\\

For Question a

2y\frac{dy}{dt}=-2x\frac{dx}{dt}\\\\\frac{dy}{dt}=\frac{-2x\frac{dx}{dt}}{2y} \\\\\frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

With x = 3, y = 4, and dx/dt = 5.

\frac{dy}{dt}=-\frac{3}{4}*5=-\frac{15}{4}\\ \\\frac{dy}{dt}=-3\frac{3}{4}

For Question b

2x\frac{dx}{dt}=-2y\frac{dy}{dt}\\\\\frac{dx}{dt}=\frac{-2y\frac{dy}{dt}}{2x} \\\\\frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}

Given x = 4, y = 3, and dx/dt = -5.

\frac{dx}{dt}=-\frac{3}{4}*-5=\frac{15}{4}\\ \\\frac{dx}{dt}=3\frac{3}{4}

5 0
25 days ago
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