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Fudgin
1 month ago
8

Nakita rode her skateboard at an average speed of 8.8 feet per second for 0.2 miles. She wants to calculate how long it took her

to skateboard that distance. Nakita uses the formula d=rt (d = distance, r = rate, t = time), and she knows that 1 mile = 5280 feet and that 1 minute = 60 seconds. How many minutes did it take Nakita to skateboard 0.2 miles at her average speed of 8.8 ft/sec?
Mathematics
1 answer:
lawyer [12.5K]1 month ago
7 0

Answer: 2\ minutes

Step-by-step explanation:

To determine time "t", we know that:

d=rt

Where "d" denotes distance, "r" signifies rate, and "t" means time.

Now isolating the time "t":

t=\frac{d}{r}

Initially, we convert miles into feet.

Since 1\ mile=5,280\ feet, thus

d=(0.2\ mi)(\frac{5,280\ ft}{1\ mi})\\\\d=1,056\ ft

Recognizing that:

r=8.8\ \frac{ft}{s}

We substitute these values into t=\frac{d}{r} to find time in seconds:

t=\frac{1,056\ ft}{8.8\ \frac{ft}{s}}\\\\t=120\ s

Given:

1\ minute = 60\ seconds

The resulting time in minutes is:

t=(120\ s)(\frac{1\ min}{60\ s})\\\\t=2\ min

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1 kilogram is equivalent to about 2.2 pounds. An orangutan weighs 142 pounds. What is its mass in kilograms? Round your answer t
AnnZ [12381]

The weight of an orangutan is 64.5 kilograms

Solution:

It is stated that the orangutan's weight is 142 pounds

Additionally,

1 kilogram is approximately 2.2 pounds

We will now convert 142 pounds into kilograms

1 kilogram = 2.2 pounds

\text{1 pound } = \frac{1}{2.2} \text{ kilograms }

As a result, 142 pounds translates to

142 \text{ pound } = \frac{1}{2.2} \times 142 \text{ kilogrmas }

\rightarrow \frac{1}{2.2} \times 142 = 64.545 \text{ kilograms }

When rounding to the nearest tenth, we obtain 64.5 kilograms

Therefore the mass of the orangutan is 64.5 kilograms

3 0
2 months ago
Eva, the owner of eva's second time around wedding dresses, currently has five dresses to be altered, shown in the order in whic
tester [12383]
To respond to this inquiry, we must assume that Eva works for 8 hours each day. If that's the case, then on the first day, Eva will complete jobs w, x, and v, amounting to six hours of work. Since job y takes 4 hours, she will only have 2 hours of work that day, leaving her with 2 hours remaining to continue on job y. The following day, she will use those 2 hours to finish job y, completing it, and also work on job z (which takes hours). Consequently, she will have tackled 4 jobs on the first day and 2 jobs on the second, resulting in an average of 3 jobs each day.
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5 0
1 month ago
Question 1(Multiple Choice Worth 2 points)
babunello [11817]
Here are 3 questions with their respective answers.

1) Find


\lim_{x \to \ 2^+} f(x)

Answer: 4.

Explanation:

This expression indicates the limit as the function f(x) approaches 2 from the right side.

You should apply the function (the line) from the right side of 2 and get as close to x = 2 as you can.

That line has an open circle at y = 4, which is the limit we are looking for.

2) Analyze the graph to see if the limit exists.

Answer:

\lim_{x \to \ 2^-} f(x) = 3

\lim_{x \to \ 2^+} f(x)=-3

To find each limit, utilize the function approaching from the direction of x.

It's important to note that since the two limits differ, it is concluded that the limit of the function as x approaches 2 does not exist.

3)
Answer: -1


\lim_{x \to \ 3^-} f(x) = -1

To determine the limit as the function approaches 3 from the left, follow the line ending with an open circle at (3, -1).

Hence, the limit is -1.
5 0
2 months ago
Read 2 more answers
Find the perimeter of a quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3). Round your answer to the ne
tester [12383]

Answer: 20 units

Step-by-step explanation:

The formula for calculating the distance between two coordinates P(a,b) and Q(c,d) is as follows:-

PQ=\sqrt{(d-b)^2+(c-a)^2}

Initially provided: The coordinates of the quadrilateral's vertices are C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).

The distance between vertices C (−2, 1) and D (2, 4) is as follows:-

CD=\sqrt{(4-1)^2+(2-(-2))^2}\\\\\Rightarrow\ CD=\sqrt{(3)^2+(4)^2}\\\\\Rightarrow\ CD=\sqrt{9+16}=\sqrt{25}\\\\\Rightarrow\ CD=5\text{ units}

Distance between points D (2, 4) and E (5, 0) is calculated as:-

DE=\sqrt{(4-0)^2+(2-5)^2}\\\\\Rightarrow\ DE=\sqrt{(4)^2+(-3)^2}\\\\\Rightarrow\ DE=\sqrt{16+9}=\sqrt{25}\\\\\Rightarrow\ DE=5\text{ units}

Distance between coordinates E (5, 0) and F (1, −3) is given by:-

EF=\sqrt{(-3-0)^2+(1-5)^2}\\\\\Rightarrow\ EF=\sqrt{(-3)^2+(-4)^2}\\\\\Rightarrow\ EF=\sqrt{9+16}=\sqrt{25}\\\\\Rightarrow\ EF=5\text{ units}

Distance from C (−2, 1) to F (1, −3) is as follows:-

FC=\sqrt{(-3-1))^2+(1-(-2))^2}\\\\\Rightarrow\ FC=\sqrt{(-4)^2+(3)^2}\\\\\Rightarrow\ FC=\sqrt{16+9}=\sqrt{25}\\\\\Rightarrow\ FC=5\text{ units}

The total perimeter of the quadrilateral is calculated as = CD + DE + EF + FC

=5+5+5+5=20\text{ units}

3 0
2 months ago
Read 2 more answers
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