For a 560-mile journey, Mrs. Allan's car will require 20 gallons of fuel. Meanwhile, Mrs. Owen's vehicle will need 16 gallons for the same distance.
To determine the time interval δt, we must subtract the starting time from the ending time. In this scenario, the first value in the coordinates signifies time:
δt=50 - 0
δt= 50s
The time interval is 50s.
The answer is $300,000. Detailed calculation: Labor cost = $11,000; Parking cost = $7,000; Therefore, Parking Labor cost = $18,000. The parking labor cost represents 6% of the parking revenue. Thus, 6% = Parking Labor cost / Parking Revenue. By substituting, we get 6/100 = $18,000 / Parking Revenue. Solving for Parking Revenue yields: Parking Revenue = (100 × $18,000) / 6 = $300,000.
It exhibits a zero slope.
In the case of a horizontal line, the slope remains constant at 0 since there is no variation.
