Response:
a) 8
b) 15
c) 34
Detailed explanation:
Section a) Options for neck-wear
Regular ties count = 3
Bow ties count = 5
Overall ties count = 3 + 5 = 8
Any tie can be selected from these 8 available options. Thus, the options for neck-wear total 8.
Section b)
We now calculate choices for using both regular and bow ties.
Selecting a regular tie is independent of the bow tie selection. According to counting principles, if two events are independent, the total ways to realize both equal the product of their individual possibilities. Thus,[
Number of ways to select both ties = Count of ways to choose each tie
So,
Ways for wearing both types of ties = 3 x 5 = 15 ways
Section c)
Count of shirts = 5
Count of skirts = 4
Count of pants = 3
Count of dresses = 7
Choice options for outfits include:
- Shirt paired with Skirt or Pants
- Or simply a dress
Pants can be chosen in 3 ways. Pairing a skirt or pant provides 9 options.
Reapplying counting rules:
Ways to wear a shirt with a skirt or pant = 3 x 9 = 27
Choices for dresses = 7
Consequently, the total is 27 + 7 = 34 outfit combinations.
Response:
14 feet
Detailed explanation:
<pThere are 3 feet for each yard, resulting in a total of 36 feet in 12 yards. The leftover ribbon will equal the initial amount minus what has been utilized.
36 - 22 = 14.... feet left
Answer:
C. The mean daily salary is not above $350 per day
Step-by-step explanation:
The calculation is displayed below:
Y = a + bX
where,
Y = earnings of a randomly chosen agent
a = $150
b = $50
X = number of loans closed
Now
E(x) = (1 × 0.05) + (2 × 0.10) + (3 × 0.22) + (4 × 0.30) + (5 × 0.18) + (6 × 0.12) + (7 × 0.03)
= 3.94
Consequently,
E(y) = $150 + ($50 × 3.94)
= $347
therefore, option C is incorrect
Respuesta:
(a) 4.98x10⁻⁵
(b) 7.89x10⁻⁶
(c) 1.89x10⁻⁴
(d) 0.5
(e) 2.9x10⁻²
Explicación paso a paso:
La probabilidad (P) de encontrar la partícula está dada por:
(1)
La solución de la integral de la ecuación (1) es:
(a) La probabilidad de encontrar la partícula entre x = 4.95 nm y 5.05 nm es:
(b) La probabilidad de encontrar la partícula entre x = 1.95 nm y 2.05 nm es:
(c) La probabilidad de encontrar la partícula entre x = 9.90 nm y 10.00 nm es:
(d) La probabilidad de encontrar la partícula en la mitad derecha de la caja, es decir, entre x = 0 nm y 50 nm es:
![P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7B2%7D%7B100%7D%20%5B%5Cfrac%7BX%7D%7B2%7D%20-%20%5Cfrac%7BSin%282%5Cpi%20x%2F100%29%7D%7B4%5Cpi%20%2F100%7D%5D%7C_%7B0%7D%5E%7B50.00%7D%20%3D%200.5%20)
(e) La probabilidad de encontrar la partícula en el tercio central de la caja, es decir, entre x = 0 nm y 100/6 nm es:
Espero que te ayude.
<span><span>Response
26 1/2 does not correspond to an integer but can be rounded to 27, which is an integer.
Clarification
An integer comprises whole numbers only. It does not include fractions.
253/2=25+3/2=25+1 1/2=26 1/2
</span><span>26 1/2 does not correspond to an integer but can be rounded to 27, which is an integer.
</span></span>