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Brilliant_brown
1 month ago
7

Olga Decorat blankets with ribbon she has 12 yards of ribbon she uses 22 feet of the ribbon to decorate blankets after she decor

ates the blanket how many feet of ribbon will remain
Mathematics
1 answer:
Svet_ta [12.7K]1 month ago
3 0

Response:

  14 feet

Detailed explanation:

<pThere are 3 feet for each yard, resulting in a total of 36 feet in 12 yards. The leftover ribbon will equal the initial amount minus what has been utilized.

  36 - 22 = 14.... feet left

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If there are 2.2 pounds in 1 kilogram how many pounds are there in x kilograms?
tester [12383]

Answer:

P=x/2.2

Step-by-step explanation:

We can set up an equation to solve this.

Let P represent the number of pounds

Let X represent the number of kilograms

Knowing that 1 kilogram equals 2.2 pounds.

So, if there is 1 kilogram (X) it translates to 2.2 pounds (P).

X=2.2P

Simply rearrange the equation to determine the pounds in x kilograms. Thus, divide both sides by 2.2.

Therefore, we derive P=x/2.2

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Brian multiplied his average speed of 14.73 miles per hour by the amount of time he spent cross-country skiing. His product was
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Yes, it was a reasonable result

Step-by-step clarification:

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27 days ago
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A battery with 20% percent of its full capacity is connected to a charger. Every minute that passes, an additional 5% percent of
Inessa [12570]

Response:

The connection between battery capacity and time is:

Y=0.05t+0.2

The associated graph is provided.

Step-by-step explanation:

We will plot the battery's charged capacity against time.

The charging rate remains steady; hence, the relationship is linear.

Initially, at time t=0, the battery's capacity measures 0.2 (or 20%).

With each passing minute, an additional 5% of its capacity is accumulated. Thus, at t=1, the capacity becomes 0.2 + 0.05 = 0.25 (or 25%).

We can derive the slope for the linear function as:

m=\dfrac{\Delta Y}{\Delta t}=\dfrac{0.05}{1}=0.05

Consequently, the correlation between battery capacity and time is:

Y=0.05t+0.2

3 0
1 month ago
What is the correct letter name for D1 below
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I believe that A is the right letter designation for D1. 
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20 days ago
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Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
Leona [12618]

To address this problem, let's start by formulating the general motion equation along the vertical direction.

This gives us:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • g: gravitational acceleration
  • vo: initial velocity
  • h0: starting height

For the first individual:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second individual:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

When both individuals reach the identical altitude, the following holds:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rearranging results in:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Solving for time:

t = 29 (\frac {12} {19})\\t = 18.31s

Result:

The two window washers reach the same height after 18.31 seconds.

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2 months ago
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