P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'
Answer:
a) The first inequality is 100 + 55x > 150 + 51x;
b) The final inequality results in x > 12.5
c) Sal's mother will need to use the second phone for at least 13 months.
Step-by-step explanation:
a) Let x represent the number of months.
1. The first phone is priced at $100, with a monthly fee of $55 for unlimited use, leading to a total cost of $(100 + 55x) for x months.
2. The second phone costs $150 with a monthly fee of $51 for unlimited use, resulting in a total of $(150 + 51x) for x months.
3. For the second phone to be cheaper, we set up the inequality:
150 + 51x < 100 + 55x
which simplifies to
100 + 55x > 150 + 51x
b) Now solve this:
55x - 51x > 150 - 100
4x > 50
so x > 12.5
c) This means Sal's mother has to retain the second phone for at least 13 months (since x > 12.5).
<span><span>Center coordinates: (x0, y0, z0)</span></span> and radius r.
<span>The equation of the sphere is:</span>
<span>(x - x0)^2 + (y - y0)^2 + (z - z0)^2 = r^2</span>
Solution:
In Mr. Skinner's class, the count of students bringing lunch from home is 12 out of 20.
Fraction of students who brought lunch from home in Mr. Skinner's class=
For Ms. Cho's class, the number who brought lunch from home is 14 out of 21.
Fraction of students who brought lunch from home in Ms. Cho's class=
Siloni is utilizing two spinners with 15 equal sections to randomly select students from the classes and predict whether they brought lunch or will purchase it from the cafeteria.
Number of Equal sections in each Spinner=15
To visualize the students from Mr. Skinner's class who brought lunch using a Spinner with 15 equal sections =
For Ms. Cho's class, using a Spinner with 15 equal sections =
Mr. Skinner's Class +1 = Ms. Cho's Class
This means that the spinner for Ms. Cho's class will include one additional section representing students who brought lunch.
Option A signifies that one additional section on Mr. Skinner's spinner represents students who brought lunch, reflecting Ms. Cho's class.
D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, presented in ascending order
Q2 (median) = d5 = 2 //middle value
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 represents the median of d1,d2,d3,d4, but as there is no singular middle element among four, the average is computed)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquartile range = IQR = Q3 - Q1 = 5 -1 = 4
final answer: 4
