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Lynna
4 months ago
13

Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independe

nt variable.
Mathematics
2 answers:
PIT_PIT [12.4K]4 months ago
8 0
They want you to isolate q
6q=3s-9
then divide both sides by 6
q=1/2s-3/2
Svet_ta [12.7K]4 months ago
4 0

Answer:

Start with the given equation:

6q = 3s -9

Add 9 to both sides:

6q+9= 3s -9+9

Simplify the result:

6q+9= 3s

Next, divide both sides by 3:

\frac{1}{3}(6q+9)=s

Apply the distributive property: a \cdot (b+c) = a\cdot b+ a\cdot c

2q+3 = s

Alternatively, it can be written as

s = 2q+3 with q as the independent variable and s as the dependent variable.

Express it in function form: s = f(q)

Thus, the equation in function notation:

f(q) = 2q+3, with q as the independent variable

You might be interested in
12x+7<−11 AND5x−8≥4012
Svet_ta [12734]

Answer:

No solution

Step-by-step explanation:

Given: 12x+7 and  5x-8\geq 40

Handle each inequality separately.

12x+7              Utilizing the subtraction property of inequalities

12x

12x

x

x

and

5x-8\geq 40               Utilizing the addition property of inequalities

5x\geq 40+8

5x\geq 48

x\geq \dfrac{48}{5}

Thus, the solution to the combined inequality is the overlap of both solutions.

Refer to the attached image for the number line representation.

No solution

8 0
3 months ago
Read 2 more answers
Tanmay had some chocolates with him. He gave one-third of them to Akash and one-fifth of them to Sharad. Tanmay could do so with
babunello [11817]

Answer:

Possible values for X include;

15, 30, 45, 60, and so on

Step-by-step explanation:

The parameters provided are

Number of chocolates Tanmay possessed = X

Number of chocolates given to Akash = 1/3 × X

Number of chocolates given to Sharad = 1/5 × X

Consequently, since both 3 and 5 divide X,

3 × 5 = 15 is the smallest single factor of X.

Thus, the values of X based on this minimum factor are as follows;

15 × 1 = 15

15 × 2 = 30

15 × 3 = 45

15 × 4 = 60

Therefore, potential values for X form an arithmetic series: a + (n - 1) × d

Where:

a = 15

n = 1, 2, 3, 4,...

d = 15

This results in;

15, 30, 45, 60

7 0
3 months ago
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