casey bought sandwiches and a bag of chips. Each sandwich cost three times as much as bag of chips. She bought 5 sandwiches for

Question

wolverine

3 days ago

14

casey bought sandwiches and a bag of chips. Each sandwich cost three times as much as bag of chips. She bought 5 sandwiches for

6 dollars each and spent 42 dollars. How many bags of chips b did she buy?

Mathematics

2 answers:

Inessa [3.9K] · Answer 1 · 2026-03-02T17:43:10+03:00

Answer:

She acquired 3 bags of chips.

Step-by-step explanation:

The price of 1 sandwich is $6.

Each sandwich costs three times as much as a single bag of chips.

Thus, the cost of a bag of chips equals $\frac{6}{3}=2$ .

Let x signify the number of chip bags she obtained.

We know that she bought 5 sandwiches priced at 6 dollars each, resulting in a total of 42 dollars.

The expense of 6 sandwiches is represented as $6 \times 6 = 36$ .

The cost of x chip bags amounts to 2x.

According to the information provided

$36+2x=42$ .

$2x=6$ .

$x=3$ .

Therefore, she purchased 3 bags of chips.

AnnZ [3.8K] · Answer 2 · 2026-03-02T17:45:05+03:00

Answer:

4

Step-by-step explanation:

Each sandwich costs 6 dollars, while chips sell for 3 dollars. She purchased 5 sandwiches at 6 dollars each, amounting to 30 dollars (5*6=30). This leaves her with 12 dollars to use since her total expenditure was 42 dollars. Given that chips are 3 dollars each, with 12 dollars left, 4 bags could be bought (4 * 3 = 12).