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MatroZZZ
3 months ago
14

Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let a = 28 lb and b = 12 lb. Round y

our answers to one decimal place.)
a = 45 degree positive on x & y axis.
b = 30 degree below x-axis. I guess negative on y & x.
Mathematics
1 answer:
AnnZ [12.3K]3 months ago
4 0

Response:

Magnitude of R = 16.7 lb

Angle = 55.7°

Stepwise explanation:

Given:

a = 28 lb

b = 12 lb

a = 45 degrees above the x & y axis.

b = 30 degrees below the x-axis, negative on y & x.

Decomposing the two forces into vector notation, we have

a = (28cos45)i + (28sin45)j

b = (-12cos30)i + (-12sin30)j

The resultant force vector R = a + b

R = (28cos45 - 12cos30)i + (28sin45 - 12sin30)j

R = 9.41i + 13.80j

Magnitude of R = √(9.41^2 + 13.80^2) = 16.7 lb

Angle = taninverse (13.80/9.41) = 55.7°

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M - 1200*x = 2000   (2)

Donde:

M: representa la incógnita correspondiente al capital del ingeniero

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De la ecuación (1) podemos deducir:

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El monto inicial del ingeniero, según la ec (3), sería:

M = 1400*50 - 8000 = 62000

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Si quieres conocer otro método para resolver sistemas de ecuaciones lineales, puedes ingresar aquí:

                                                                                         

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1 month ago
One similar figure has an area that is nine times the area of another. The larger figure must have dimensions that are times the
Svet_ta [12734]
T<span>he area of a figure signifies the measure of space within a two-dimensional shape, typically expressed as square units based on the figure's dimensions.

For instance, with a shape having dimensions of k, its area can be given by k^2.
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<span>Consider that one similar figure possesses an area nine times that of another.

As these figures are similar, their areas correspond to the proportionality of their dimensions.

Let the smaller shape's dimensions be k, while the larger is p times the dimensions of the smaller shape. The smaller shape's area is k^2 and the larger shape's area is (pk)^2.

Now, knowing the larger figure's area is nine times the area of the smaller figure, we have:
\frac{(pk)^2}{k^2} = \frac{9}{1} \\ \\ \frac{p^2k^2}{k^2} =9 \\ \\ p^2=9 \\ \\ p= \sqrt{9} \\ \\ p=3
</span>
Thus, the dimensions of the larger figure must be 3 times those of the smaller figure.
3 0
1 month ago
Read 2 more answers
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