Write code that prints: Ready! countNum ... 2 1 Blastoff! Your code should contain a for loop. Print a newline after each number

Question

Vsevolod

3 months ago

3

Write code that prints: Ready! countNum ... 2 1 Blastoff! Your code should contain a for loop. Print a newline after each number

and after each line of text Ex: countNum = 3 outputs: Ready! 3 2 1 Blastoff!

Computers and Technology

2 answers:

Harlamova29_29 [1K] · Answer 1 · 2026-02-18T02:31:00+03:00

Response:

C# Code:

#include <stdio.h>

// main function initiated

int main()

{

// variables declared

int userNum = 0;

int i = 0;

// assign userNum to 3

userNum = 3;

// print 'Ready!'

printf("Ready!");

// print new line

printf("\n");

// for-loop to print userNum ... 2 1

for (i = userNum; i >= 1; i--)

{

// print current 'i' value

printf("%d", i);

// print new line

printf("\n");

} // for-loop concluded

// print 'Blastoff!'

printf("Blastoff!");

// new line printed

printf("\n");

// exit program

return 0;

} // main function concluded

Details:

oksian1 [950] · Answer 2 · 2026-02-18T02:32:41+03:00

Response:

import java.util.Scanner;

public class BlastOff {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.print("Enter Count Down Number: ");

int countNum = in.nextInt();

System.out.println("Ready!");

for(int i = countNum; i>0; i--){

System.out.println(i);

}

System.out.println("Blastoff!");

}

Details:

Using Java programming:

Request and acquire countdown number from the user with the scanner class
Display the text Ready! System.out.println("Ready!");
Utilize for loop to output numbers from countNum down to 1
After the loop, print Blastoff! System.out.println("Blastoff!");
Ensure that each output is on its separate line with .println()