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Yuki888
3 days ago
8

Beth is putting liquid fertilizer on the plants in 4 flowerpots. her measuring spoon holds 1/8 teaspoon the directions say to pu

t 5/8teaspoons of fertilizer in each pot how many times will both need to fill the measuring spoon to fertilize the plants in the four pots
Mathematics
2 answers:
zzz [4K]3 days ago
5 0
20 multiplied by 1/8 plus 1/8 plus 1/8 plus 1/8 plus 1/8 equals 5/8 times 4, due to the four pots, resulting in 20.
Inessa [3.9K]3 days ago
4 0
She must fill the measuring spoon 20 times.
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A formula calls for 0.6 mL of a coloring solution. Using a 10-mL graduate calibrated from 2 to 10 mL in 1-mL units, how could yo
PIT_PIT [3949]

Answer:

We will mix 2.4 mL of water with 0.6 mL of the coloring solution.

The total solution volume amounts to 2.4 + 0.6, which equals 3 mL.

Therefore,

0.6 mL of coloring solution now contains 2.4 mL of water.

Alternatively,

1 mL of this coloring solution comprises 4 mL of water.

Thus,

We should prepare 3 mL of the coloring solution with the resultant water.

This 3 mL mixture will encapsulate 0.6 mL of the coloring solution.

Step-by-step explanation:

As stated:

The formula requires 0.6 mL of a coloring solution.

Using a 10-mL graduated cylinder that is divided from 2 to 10 mL in 1-mL increments:

We aim to apply the aliquot method to accurately measure 0.6 mL of the coloring solution.

Given that the graduated cylinder measures from 2mL to 10mL only, we'll blend 2.4 mL of water with 0.6 mL of coloring solution.

Thus, the total solution volume is 2.4 + 0.6, resulting in 3 mL.

Consequently,

This implies that 0.6 mL of coloring solution now carries 2.4 mL of water.

Additionally,

1 mL of coloring solution encapsulates 4 mL of water.

Hence,

We will quantify 3 mL of the final solution, which contains 0.6 mL of coloring solution.

3 0
9 days ago
What positive integer is closest to the value of √230 ?
Svet_ta [4341]

Response:

15

Detailed explanation:

sqrt230=15.165...

9 0
9 days ago
Read 2 more answers
Read the proof. Given: m∠H = 30°, m∠J = 50°, m∠P = 50°, m∠N = 100° Prove: △HKJ ~ △LNP Statement Reason 1. m∠H = 30°, m∠J = 50°,
zzz [4035]

Answer:

2. m\angle H+m\angle J +m\angle K =180^{\circ}

Reason: the total sum of all angles inside any triangle equals 180º.

Step-by-step explanation:

1) Organization

Statement 1. m∠H = 30°, m∠J = 50°, m∠P = 50°, m∠N = 100° 1. Reason: given

2) Given that the sum of all internal angles in any triangle is always 180º, similar to the formula. N represents the number of sides of a triangle:

S_{i}=180^{\circ}(n-2)\rightarrow 180(3-2) \therefore S_{i}=180^{\circ}

3) We can also state

m\angle K=180^{\circ}-(m\angle H+m\angle J)\\m\angle K=180^{\circ}-\left ( 30^{\circ}+50^{\circ} \right )\\m\angle K=100^{\circ}

Like in the other triangle:

m\angle L=180^{\circ}-(m\angle N+m\angle P)\\m\angle L=180^{\circ}-\left ( 100^{\circ}+50^{\circ} \right )\\m\angle L=30^{\circ}

4) Therefore,

2. m\angle H+m\angle J +m\angle K =180

Reason: The total of the internal angles is equal to 180º.

8 0
1 day ago
This picture of a wall hanging is made of congruent 30° − 60° − 90° triangles with height 6 cm and hypotenuse 12 cm. What is the
Svet_ta [4341]

Answer:

28.4 cm

Step-by-step explanation:

The perimeter of the triangular wall is determined by adding all sides of the right triangle.

The triangle's height is given as 6 cm.

The hypotenuse measures 12 cm.

Using the Pythagorean theorem to find the third side:

Hypotenuse² = opposite² + adjacent²

Assigning the height as opposite = 6 cm, we find:

12² = 6² + adj²

Thus, adj² = 12² - 6²

Which gives us adj² = 144 - 36

So, adj² = 108

Leading to adj = √108

Thus, adj = 10.39 cm

The perimeter totals = 6 cm + 12 cm + 10.39 cm

= 28.39 cm

= 28.4 cm when rounded to the nearest tenth.

6 0
6 days ago
A breed of cattle needs at least 10 proteins and 8 fats units per day. Feed type I provides 6 protein and 2 fat units at $4 per
tester [3938]
Let x represent the amount of feed type I and y the amount of feed type II to be utilized. Our goal is to minimize the following:

C = 4x + 3y

while adhering to these constraints:

6x+2y\geq10 \\ \\ 2x+3y\geq8 \\ \\ x\geq0,\ y\geq0

Analyzing the graph of these four constraints yields corner points at (0, 5), (1, 2), and (4, 0).

Testing the objective function at each corner point to find the minimum:

For (0, 5):
C = 4(0) + 3(5) = $15

For (1, 2):
C = 4(1) + 3(2) = 4 + 6 = $10

For (4, 0):
C = 4(4) + 3(0) = $16.

Thus, the combination that results in the lowest cost is one bag of feed type I and two bags of feed type II.
7 0
4 days ago
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