12 m^2/h to cm^2/min
12 m^2/h × 1 h/60 min = 0.2 m^2/min
0.2 m^2/min × 10000 cm^2/1 m^2 = 2000 cm^2/min
2000 cm^2/min
Answer:
________{0.50 if x < 3
________{1.00 if 3 ≤ x < 6
f(x) = ____{1.50 if 6 ≤ x < 9
________{2.00 if 9 ≤ x < 12
Step-by-step explanation:
Based on the details provided:
Employees with less than 3 years receive an increase of $0.50 hourly
Employees with at least 3 years but under 6 years receive $1.00 increase hourly
Employees with a minimum of 6 years and less than 9 get $1.50 increase hourly
Employees with at least 9 years but below 12 years receive $2.00 increase hourly
This information can be expressed as a piecewise function:
________{0.50 if x < 3
________{1.00 if 3 ≤ x < 6
f(x) = ____{1.50 if 6 ≤ x < 9
________{2.00 if 9 ≤ x < 12
The conditions are outlined in the piecewise function above with x indicating the number of years employed.
The first equation is x + y = 29, and the second is 5x + 2y = 100.
Response:
Detailed explanation:
The final result is 3 /8/33.
step by step breakdown
Initially, we write:
x
=
3
.
¯¯¯¯
24
After that, we will multiply each side by
100
leading to:
100
x
=
324
.
¯¯¯¯
24
Subsequently, we will subtract the first equation from the second equation:
100
x
−
x
=
324
.
¯¯¯¯
24
−
3
.
¯¯¯¯
24
We can then solve for
x
in the following manner:
100
x
−
1
x
=
(
324
+
0
.
¯¯¯¯
24
)
−
(
3
+
0
.
¯¯¯¯
24
)
(
100
−
1
)
x
=
324
+
0
.
¯¯¯¯
24
−
3
−
0
.
¯¯¯¯
24
99
x
=
(
324
−
3
)
+
(
0
.
¯¯¯¯
24
−
0
.
¯¯¯¯
24
)
99
x
=
321
+
0
99
x
=
321
99
x
99
=
321
99
99
x
99
=
3
×
107
3
×
33
x
=
3
×
107
3
×
33
x
=
107
33
Next, we convert this improper fraction to a mixed numeral:
x
=
107
33
=
99
+
8
33
=
99
33
+
8
33
=
3
+
8
33
=
3
8
33
3
.
¯¯¯¯
=
3
8
33
Density can be defined as:
Where:
m is mass
V stands for volume
To isolate the mass, we derive:
Volume can be expressed as:
We then use the following conversion:
After applying the conversion, we arrive at:
Additionally, we have these conversions:
When we apply these conversions for density, we conclude:
Finally, the mass of the water required is:
Answer:
A total of 1190 kilograms of water is needed to fill the waterbed.
