The density of nuclear matter is about 1018 kg/m3. Given that 1 mL is equal in volume to 1 cm3, what is the density of nuclear m

Question

2 days ago

11

atter in megagrams per microliter (that is, Mg/µL)?

2 answers:

Sav [1.1K] · Answer 1 · 2026-03-03T00:00:19+03:00

Answer:

The density comes out to be $10^{6}$ Mg/µL

Explanation:

Given data:

The density of nuclear matter is approximately $10^{18}$ kg/m³

1 ml corresponds to 1 cm³

To determine:

The density of nuclear matter in Mg/µL

Solution:

We recognize that:

1 Mg equals 1000 kg

Thus, 1 m³ is equal to $10^{6}$ cm³

Moreover, 1 cm³ is equivalent to 1 mL

Thus, we can conclude that 1 mL is equal to 10³ µL

With this, we convert the density as follows:

Density = $10^{18}$ kg/m³

Density = $10^{18}$ kg/m³ × $\frac{10^{-3} }{10^{6} }$ Mg/µL

Density = $10^{6}$ Mg/µL

kicyunya [1K] · Answer 2 · 2026-03-03T00:00:12+03:00

kicyunya [1K]2 days ago

3 0

Answer: The density of nuclear matter will be $10^{-12}Mg/\mu L$

Explanation:

Density is defined as the mass per unit volume.

$Density=\frac{mass}{Volume}$

Given:

The density of nuclear matter = $1018kg/m^3$

1 ml = $1cm^3$

1 kg = 0.001 Mg

Thus $1018kg=\frac{0.001}{1}\times 1018=1.018Mg$

Additionally $1m^3=10^9\mu L$

Substituting the values yields:

$Density=\frac{0.001Mg}{10^9\mu L}=10^{-12}Mg/\mu L$

Consequently, the density of nuclear matter will be $10^{-12}Mg/\mu L$