Your school science club has devised a special event for homecoming. You've attached a rocket to the rear of a small car that ha
1 answer:
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Answer:
The resulting velocity for him will be 0.187 m/s in reverse direction.
Explanation:
Given:
The mass of the man is,
The mass of the ball is,
The initial velocity of the man is,
The initial velocity of the ball is,
The final velocity of the ball is,
The final velocity of the man is,
To determine this scenario, we employ the principle of momentum conservation.
This principle states that the total initial momentum equals the total final momentum.Momentum is calculated by multiplying mass by velocity.
Initial momentum = Initial momentum of the man and the ballInitial momentum =
Final momentum = Final momentum of the man and the ball
Final momentum =
Hence, the total initial momentum equals the total final momentum
The negative sign indicates that the man moves backward.
Thus, his final velocity ends up being 0.187 m/s backward.
Answer:
35.79 meters
Explanation:
We have an archer, and there is a target. Denote the distance between them as d.
The bowman releases the arrow, which travels the distance d at a velocity of 40 m/s until it hits the target. We establish the equation as:
Right after this, the arrow produces a muffled noise, traveling the same distance d at a speed of 340 m/s in time . Thus, we can derive:
.
Consequently, the sound reaches the archer, precisely 1 second post-firing the bow, resulting in:
.
Using this relationship in the distance formula for sound allows us to write:
.
Substituting the value of d from the first equation yields:
.
Now, after some calculations, we can proceed further:
.
Finally, the value is inserted into the initial equation:
Answer:
La magnitud del momento total es de 21.2 kg m/s y su dirección es de 39.5° respecto al eje x.
Explanation:
¡Hola!
El momento total se calcula como la suma de los momentos de las piezas.
El momento de cada pieza se calcula de la siguiente manera:
p = m · v
Donde:
p = momento.
m = masa.
v = velocidad.
El momento es un vector. La pieza de 200 g se mueve a lo largo del eje x, por lo que su momento será:
p = (m · v, 0)
p = (0.200 kg · 82.0 m/s, 0)
p = (16.4 kg m/s, 0)
La pieza de 300 g se mueve a lo largo del eje y. Su vector momento será:
p =(0, m · v)
p = (0, 0.300 kg · 45.0 m/s)
p = (0, 13.5 kg m/s)
El momento total es la suma de cada momento:
Momento total = (16.4 kg m/s, 0) + (0, 13.5 kg m/s)
Momento total = (16.4 kg m/s + 0, 0 + 13.5 kg m/s)
Momento total = (16.4 kg m/s, 13.5 kg m/s)
La magnitud del momento total se calcula de la siguiente manera:
La dirección del vector de momento se calcula utilizando trigonometría:
cos θ = px/p
Donde px es el componente horizontal del momento total y p es la magnitud del momento total.
cos θ = 16.4 kg m/s / 21.2 kg m/s
θ = 39.3 (39.5° si no redondeamos la magnitud del momento total)
<pFinalmente, la magnitud del momento total es 21.2 kg m/s y su dirección es 39.5° respecto al eje x.