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zepelin
2 days ago
6

Chris has a cell phone plan with a flat fee of $26.00 per month, plus a cost of $0.12 per minute of usage. Chris can only afford

a monthly bill of $86.00. Which statement is true? A. Chris needs to use fewer than 400 minutes per month. B. Chris needs to use fewer than 450 minutes per month. C. Chris can afford to use up to 500 minutes per month. D. Chris can afford to use up to 550 minutes per month.
Mathematics
1 answer:
tester [3.9K]2 days ago
3 0

For Chris, the calculation for his monthly telephone expense is as follows:

C (x) = 26 + 0.12x

Where "x" denotes each minute used.

Given that Chris can afford a bill of $86, we have:

26 + 0.12x \leq86\\0.12x \leq86-26\\0.12x \leq60\\x \leq \frac {60} {0.12}\\x \leq500

The total minutes of usage must not exceed 500 per month. Consequently, the viable choice is option C.

Answer:

Option C

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Answer:

The detailed work and solution can be found in the attachment

Step-by-step explanation:

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2 days ago
The graphs below have the same shape. The equation of the blue graph is f(x)=x^2. Which of these is the equation of the red grap
tester [3938]
We observe that
the vertex of f(x) is located at the point (0,0)
and
the vertex of g(x) is situated at (0,5)

thus,
(x,y) in f(x)  becomes -------> (x,y+5) in g(x)
g(x)---------> f(x)+5

g(x)=x²+5

the answer is
g(x)=x²+5

4 0
9 days ago
A factory received a shipment of 38 sprockets, and the vendor who sold the items knows there are 5 sprockets in the shipment tha
tester [3938]

Answer:

a) 0.00019923%

b) 47.28%

Step-by-step explanation:

a) To determine the likelihood that all sockets in the sample are defective, we can use the following approach:

The first socket is among a group that has 5 defective out of 38, leading to a probability of 5/38.

The second socket is then taken from a group of 4 defective out of 37, following the selection of the first defective socket, resulting in a probability of 4/37.

Extending this logic, the chance of having all 5 defective sockets is computed as: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%.

b) Using similar reasoning as in part a, the first socket has a probability of 33/38 of not being defective as it's chosen from a set where 33 sockets are functionally sound. The next socket has a proportion of 32/37, and this continues onward.

The overall probability calculates to (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%.

5 0
7 days ago
Un globo vuela entre dos ciudades A y B, que distan entre sí 1.500 m. Los tripulantes del globo ven la ciudad A con un ángulo de
Inessa [3926]

Respuesta:

La altitud del globo por encima del nivel del suelo es de 449,6 metros.

Explicación paso a paso:

El enunciado no está completo. El texto completo es: "Un globo se desplaza entre las ciudades A y B, que se encuentran a 1.500 m de distancia. Los ocupantes del globo observan la ciudad A con un ángulo de depresión de 27°, mientras que, para la ciudad B, el ángulo es de 36°. ¿Cuál es la altura aproximada del globo con respecto al suelo?"

El diagrama que ilustra esta situación está en el archivo adjunto. Para calcular la altura del globo, se pueden emplear las funciones trigonométricas, siendo recomendable hacer uso de la función tangente para los ángulos de depresión mencionados:

Ciudad A

\tan 27^{\circ} = \frac{h}{1500\,m-x}

0,510 = \frac{h}{1500\,m-x}

Ciudad B

\tan 36^{\circ} = \frac{h}{x}

0,727 = \frac{h}{x}

Donde h y x representan la altura desde el suelo y la distancia horizontal desde la ciudad A.

Luego, se igualan las alturas en ambas ecuaciones para calcular la distancia horizontal del globo en relación a la ciudad A:

0,727\cdot x = 0,510\cdot (1500\,m-x)

1,237\cdot x = 765\,m

x = 618,432\,m

Por último, la altura del globo sobre el suelo se calcula como:

h = 0,727\cdot x

h = 0,727\cdot (618,432\,m)

h = 449,600\,m

La altura del globo respecto al nivel del suelo es 449,6 metros.

6 0
11 days ago
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Svet_ta [4341]

The likelihood of selecting one girl is calculated as \frac{5}{12}. This is based on having 5 girls within a total of 12 students, and the probability of an event can be expressed as: \frac{\text{# of things you want}}{\text{# of things are possible}}.

Using the same reasoning, for the next student, we have reduced the number of students by 1, leading to 11 possible outcomes instead of 12, giving us:\frac{7}{11}, which represents the probability of selecting a boy as the second choice.

Lastly, the probability of choosing a girl for the third selection follows the same logic and is given as:\frac{4}{10}.

However, we must combine these individual probabilities to determine the likelihood of this specific sequence of selections occurring:

\frac{5}{12}*\frac{7}{11}*\frac{4}{10}=\frac{140}{1320}

This simplifies to:

\frac{7}{66}

4 0
8 days ago
Read 2 more answers
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