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Nadusha1986
3 months ago
6

Volunteers at an animal shelter are building a rectangular dog run so that one shorter side of the rectangle is formed by the sh

elter building as shown. They plan to spend between​ $100 and​ $200 on fencing for the sides at a cost of​ $2.50 per ft. Write and solve a compound inequality to model the possible length of the dog run.

Mathematics
1 answer:
lawyer [12.5K]3 months ago
7 0

Answer:

The detailed work and solution can be found in the attachment

Step-by-step explanation:

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Select the correct answer from each drop-down menu.
AnnZ [12381]

Answer:

The answer is 7

Step-by-step explanation:

To find the base area of the triangular pyramid:

(base x height) / 2 = (4 x 3.5) / 2 = 7 in²

5 0
3 months ago
Read 2 more answers
Given A is between Y and Z and YA=22, AZ=16x, and YZ=166, find AZ
AnnZ [12381]


YA + AZ = YZ

22 + 16x = 166

16x = 166 - 22

16x = 144

x = 144/16

x = 9

AZ = 144

8 0
2 months ago
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Profit:p=r-c;solve for c
tester [12383]
If you want to rearrange p = r - c to express c, you can follow these steps:

p = r - c         /+c
p + c = r - c + c
p + c = r       /-p
p + c - p = r - p
c = r - p

The correct form is c = r - p.
5 0
3 months ago
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Researchers measured the average blood alcohol concentration C(t) of eight men starting one hour after consumption of 30 mL of e
babunello [11817]

Answer:

Please review the explanation

Detailed explanation:

Based on the data provided:

Time, t (hours)__1.0__1.5__2.0__2.5__3.0

C(t) (mg/mL)__0.35_0.26_0.20_0.14_0.09

Average change of C with respect to t over the interval:

(i) [1.0, 2.0] (ii) [1.5, 2.0] (iii) [2.0, 2.5] (iv) [2.0, 3.0]

Average change is calculated as ( change in C / change in t) = C2 - C1 / t2 - t1

1) [1.0, 2.0]

C at t = 1 = 0.35; C at t = 2 = 0.20

(0.20 - 0.35) / (2 - 1) = - 0.15 / 1 = - 0.15 mg/mL hr

11) [1.5, 2.0]

(0.20 - 0.26) / (2.0 - 1.5) = - 0.06 / 0.5 = - 0.12 mg/mL hr

111) [2.0, 2.5]

(0.14 - 0.20) / (2.5 - 2.0) = - 0.06 / 0.5 = - 0.12mg/mL hr

iv) [2.0, 3.0]

(0.09 - 0.20) / (3.0 - 2.0) = - 0.11 / 1.0 = - 0.11 mg/mL hr

4 0
1 month ago
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