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Cloud
3 months ago
9

Value of sec Square 26 degrees - cot square 64 degrees is

Mathematics
1 answer:
Leona [12.6K]3 months ago
4 0

Answer:

The value equals 1

Step-by-step explanation:

Consider the expression

sec^{2}(26\°)-cot^2(64\°)

Recall that

cot^2(64\°)=\frac{cos^2(64\°)}{sin^2(64\°)}

sec^{2}(26\°)=\frac{1}{cos^2(26\°)}

For two complementary angles A and B (where A+B=90°),

the identity is

cos(A) = sin(B)

Here, 26° and 64° are complementary angles, so

\frac{1}{cos^2(26\°)}=\frac{1}{sin^2(64\°)}

Substituting values,

\frac{1}{sin^2(64\°)}-\frac{cos^2(64\°)}{sin^2(64\°)}

\frac{1-cos^2(64\°)}{sin^2(64\°)}

From this, we find

1-cos^2(64\°)=sin^2(64\°)

By substitution,

\frac{sin^2(64\°)}{sin^2(64\°)}=1

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