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erastovalidia
2 months ago
14

A ball is launched into the sky at 19.6 feet per second from a 58.8 meter tall building. The equation for the ball's height. h,

at time t seconds is h=-4.9t^2+19.6t+58.8. When will the ball strike the ground
Mathematics
1 answer:
tester [12.3K]2 months ago
3 0
H represents the height of the ball at a specific time, denoted by t. To determine when it reaches the ground, we need to set h to 0. The equation translates to 0 = -4.9t² + 19.6t + 58.8, leading to 0 = 4.9t² - 19.6t - 58.8, then simplified to 0 = t² - 4t - 12. Factoring yields 0 = (t - 6)(t + 2), giving solutions of t = 6 or -2. However, since time cannot be negative, the ball will hit the ground after 6 seconds.
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2 months ago
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