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rjkz
2 days ago
15

Alonso brings \$21$21dollar sign, 21 to the market to buy eggs and avocados. He gets eggs that cost \$2.50$2.50dollar sign, 2, p

oint, 50. Then, he notices that the store only sells avocados in bags of 333 for \$5$5dollar sign, 5. He wants to buy as many avocados as he can with his remaining money. Let BBB represent the number of bags of avocados that Alonso buys. 1) Which inequality describes this scenario?
Mathematics
1 answer:
PIT_PIT [9.1K]2 days ago
8 0

Answer:

B ≤ 11 bags

Step-by-step explanation:

Alonso starts with $21. After purchasing eggs for $2.50, he has $21 - $2.50 left = $18.50

Thus, the remaining money for avocados is $18.50.

Each 3 bags of avocados cost $5, making the price for 1 bag $(5/3)

Consequently, if B represents the quantity of avocado bags purchased by Alonso, it could be expressed as:

B ≤ $18.50 ÷ $(5/3)

B ≤ 11.1

B ≤ 11

B ≤ 11 bags

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1,459.75 - 200.25 - 359.45 - 125.00 - 299.35 = 475.70

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11 days ago
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Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
Zina [9171]

Response:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) signifies the likelihood that a student with a visa card also possesses a MasterCard.

p(A/B) indicates the probability that a student with a MasterCard also has a visa card.

e. 0.35

f. 0.31

Detailed explanation:

a. p(AUBUC) = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + P(AnBnC)

        = 0.6 + 0.4 + 0.2 - 0.3 - 0.11 - 0.1 + 0.07 = 0.76

b. P(AnBnC') = P(AnB) - P(AnBnC)

        = 0.3 - 0.07 = 0.23

c. P(B/A) = P(AnB)/P(A)

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e. P((AnB)/C) = P((AnB)nC)/P(C)

        = P(AnBnC)/P(C)

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f. P((AUB)/C) = P((AUB)nC)/P(C)

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7 0
20 days ago
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This leads to b=27sin17/sin53, c=27sin110/sin53

The perimeter is defined as a+b+c, so

p=27+27sin17/sin53+27sin110/sin53 units

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(x+7)(???)=???

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