Two student are reading a book. Keith reads 6 pages a day.tameka read 5 pages a day but he start sooner and has already read 15

Hello from MrBillDoesMath!

Answer:

-52. None of the alternatives presented is accurate

Discussion:

Based on standard mathematical operations, none of the given solutions is correct. The calculation results in

2*3 + 4- 62 =                => * before + and -

(2*3) + 4 - 62=             => 2*3 = 6

6 + 4 -62 =                   => 6 + 4 = 10

10 - 62 =

-52

Thank you,

MrB

A.) P(t) = P0e^(kt)
P(20/60) = 40 e^(20k/60)
80 = 40 e^(k/3)
e^(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)

b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells

d.) Rate of change = e^(8k) = e^(8(3ln(2))) = e^(24ln(2)) = e^(16.6355) = 16777216 cells/hour

e.) P(t) = 40(2)^(3t); t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours

The first equation is x + y = 29, and the second is 5x + 2y = 100.

Esto no puede ser correcto ya que si hay 60 coches, eso implica 240 ruedas de coches, y 25 bicicletas significan 50 ruedas de bicicletas, lo que suma un total de 290 ruedas. Si hubiera 1 coche adicional, habría 86 vehículos y 294 ruedas, o si se agregaran 2 bicicletas más, eso resultaría en 87 vehículos y 294 ruedas.

Let’s tackle the problem. We know the formula for <span>the height of the ball is as follows:

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Here, x represents </span><span>the horizontal distance in yards that the ball has traveled in the air. Given that distance is always a positive value, we conclude that x must be greater than or equal to 0. Thus:

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The horizontal plane indicates the function's zero point, and since the ball cannot have negative height values, must also remain positive. Ultimately, the graph reveals that the suitable domain is:

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