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Gemiola
2 months ago
15

$abcd$ is a square. how many squares have two or more vertices in the set $\{a, b, c, d\}$?

Mathematics
2 answers:
AnnZ [12.3K]2 months ago
7 0

Response:

13

Detailed explanation:

There are (4 choose 2) = 6 methods to select two points P and Q from the group of four points {A, B, C, D}. With P and Q as adjacent vertices, two squares can be constructed (one next to each side of PQ), and one square can be formed with P and Q acting as opposite vertices. This results in a total of 6 x 3 = 18 squares.

Nevertheless, we need to exclude duplicates. The original square ABCD was counted 6 times, which leads to a final count of actual squares being 18 - 5 = 13.

PIT_PIT [12.4K]2 months ago
7 0
There are four squares whose sides match one of the sides of square abcd.

Additionally, there are four squares that have sides corresponding to the diagonals of square abcd.

Finally, consider the original square

Thus, we have 4 + 4 + 1 = 9 squares <span>that contain at least two vertices within the set {a, b, c, d}.</span>
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Maureen McIlvoy, owner and CEO of a mail order business for wind surfing equipment and supplies, is reviewing the order filling
lawyer [12517]

Response:

Maureen's null hypothesis is, H₀: p₁ ≥ p₂.

Detailed explanation:

Maureen McIlvoy, as the owner and CEO of a mail-order business specializing in windsurfing gear, is scrutinizing the order fulfillment processes in her warehouses. Her objective is to achieve a 100% shipment rate of orders within 24 hours. Upon examining her warehouse operations, she discovers that both the East coast and West coast warehouses have not met this goal, although the East Coast warehouse has consistently outperformed its counterpart.

To verify this finding, Maureen’s team randomly sampled 200 orders from the West Coast warehouse (population 1) and 400 from the East Coast warehouse (population 2).

Of the sampled 200 orders from the West Coast warehouse, 190 were delivered within the specified time. In contrast, 372 out of 400 orders from the East Coast warehouse were processed within 24 hours.

The hypotheses can be formulated as followed:

H₀: The proportion of timely shipments from the East Coast does not exceed that from the West Coast warehouse, thus, p₁ ≥ p₂.

Hₐ: The proportion of timely shipments from the East Coast warehouse is indeed greater than that from the West Coast warehouse, stated as p₁ < p₂.

Thus, Maureen's null hypothesis becomes, H₀: p₁ ≥ p₂.

8 0
2 months ago
Complete the sentence below. If (3x2 + 22x + 7) ÷(x + 7) = 3x + 1, then (x + 7)(???????) =???? .
Zina [12379]

Response: The outcome is (x+7)(3x+1)=33x^2+22x+7.

Detailed explanation: Suppose that

(3x2 + 22x + 7) \div(x + 7) = 3x + 1,

we need to finalize the subsequent sentence:

(x+7)(???)=???

We have the polynomial division algorithm as follows

\textup{If }a(x)\times b(x)=c(x),\\\textup{then, we have }\\\\\dfrac{c(x)}{b(x)}=a(x)~~~~~\textup{or}~~~~~~c(x)\div b(x)=a(x).

In this equation, a(x) denotes the quotient, b(x) indicates the divisor, and c(x) stands for the dividend.

Using this principle in the current problem, it results in

\textup{since }(3x2 + 22x + 7) \div(x + 7) = 3x + 1,\\\\\textup{so, }\\\\(x+7)(3x+1)=3x^2+22x+7=0.

Consequently, the full sentence would be

(x+7)(3x+1)=3x^2+22x+7=0.

7 0
2 months ago
Read 2 more answers
What is a3 in an arithmetic sequence in which a10=41 and a15=61
zzz [12365]
\bf \begin{array}{llll}&#10;term&value\\&#10;-----&-----\\&#10;a_{10}&41\\&#10;a_{11}&41+d\\&#10;a_{12}&(41+d)+d\\&#10;&41+2d\\&#10;a_{13}&(41+2d)+d\\&#10;&41+3d\\&#10;a_{14}&(41+3d)+d\\&#10;&41+4d\\&#10;a_{15}&(41+4d)+d\\&#10;&41+5d=61&#10;\end{array}&#10;\\\\\\&#10;41+5d=61\implies 5d=20\implies d=\cfrac{20}{5}\implies \boxed{d=4}\\\\&#10;-------------------------------\\\\

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;d=4\\&#10;n=10\\&#10;a_{10}=41&#10;\end{cases}&#10;\\\\\\&#10;41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

therefore

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;d=4\\&#10;n=3\\&#10;a_{1}=5&#10;\end{cases}&#10;\\\\\\&#10;a_3=a_1+(3-1)4\implies a_3=5+(3-1)4

and you are probably aware of the amount.
8 0
1 month ago
Read 2 more answers
Alonso brings \$21$21dollar sign, 21 to the market to buy eggs and avocados. He gets eggs that cost \$2.50$2.50dollar sign, 2, p
PIT_PIT [12445]

Answer:

B ≤ 11 bags

Step-by-step explanation:

Alonso starts with $21. After purchasing eggs for $2.50, he has $21 - $2.50 left = $18.50

Thus, the remaining money for avocados is $18.50.

Each 3 bags of avocados cost $5, making the price for 1 bag $(5/3)

Consequently, if B represents the quantity of avocado bags purchased by Alonso, it could be expressed as:

B ≤ $18.50 ÷ $(5/3)

B ≤ 11.1

B ≤ 11

B ≤ 11 bags

8 0
1 month ago
The height of a triangular road sign is 1 inch shorter than twice its base. if the area of the sign is 60 in.2, which equation c
Inessa [12570]
Comment
Let's first tackle the simplest approach to finding the area of a triangle.

Formula for area is
A = 1/2 b * h

Substituting values
Area = 60 in^2
where b = x
and h = 2x - 1 
Thus, 60 = 1/2 * x * (2x - 1)

Now, we solve
60 = 1/2 * x (2x - 1) Multiply by 2
60 * 2 = x(2x - 1)
120 = x (2x - 1) Expand the brackets.
120 = 2x^2 - x  Subtract 120 from both sides.
2x^2 -  x - 120 = 0 which factors out to
(2x + 15)(x - 8) = 0

Now, solving for x
2x + 15 = 0
2x = - 15
thus, x = -15/2
which yields a negative value, hence discard this solution.

x - 8 = 0
gives us x = 8 

Area verification
base = 8
height = 16 - 1 = 15

thus Area = 1/2 * 8 * 15 = 60 confirming the calculation

Response
Utilize Area = 1/2 * b * h to determine both the base and height.
6 0
1 month ago
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