R+5/mn=p solve for m

Response:

b

Detailed explanation:

because that's the solution jfjfjdkdkdkdkdjdmf

For a 560-mile journey, Mrs. Allan's car will require 20 gallons of fuel. Meanwhile, Mrs. Owen's vehicle will need 16 gallons for the same distance.

The gross margin would be reduced to 34%.

Approximately 2, I believe... I calculated it to be around 2.10. 

We determine that the true average calorie content as estimated in the sampled population surpasses the actual calorie content. Step-by-step explanation: An article discussed a pilot study where each of the 58 participants was asked to estimate the calorie count of a 12 oz beer known to have 153 calories. The observed sample mean of calorie estimation was 193, with a sample standard deviation of 88. Let = true average estimated calorie level within the sampled population. Thus, Null Hypothesis, : 153 calories {indicating that the true average estimated calorie content does not exceed the actual amount}. Alternative Hypothesis, : > 153 calories {indicating the true average estimation exceeds the actual}. The appropriate test statistic would be a one-sample t-test statistic, as we lack knowledge of the population standard deviation; Test Statistic = ~t =

where, sample mean estimated calorie level = 193 calories, s = sample standard deviation = 88, and n = sample size = 58. Therefore, the test statistic = ~t = 3.462. The t-table indicates a critical value of 1.6725 for 57 degrees of freedom at a 0.05 significance level. Since our test statistic of 3.462 > 1.6725, we have sufficient evidence to reject the null hypothesis; thus, affirming that the true average estimated calorie content in the sampled population exceeds the real content.