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suter
2 days ago
13

An object is at rest on the ground. The object experiences a downward gravitational force from Earth. Which of the following pre

dictions is correct about why the object does not accelerate downward? Select two answers. Justify your selections.A) The bonded molecules of the object are repelled upward by the bonded molecules of the ground with the same magnitude as the gravitational force downward on the object.B)The normal force is exerted upward on the object from the ground with the same magnitude as the gravitational force downward on the objectC) The bonded molecules of the object are attracted downward by the bonded molecules of the ground with the same magnitude as the gravitational force downward on the object.D) The force of friction is exerted upward on the object from the ground with the same magnitude as the gravitational force downward on the object.
Physics
2 answers:
Yuliya22 [1.1K]2 days ago
6 0

Answer:

A) and B) are valid.

Explanation:

When an object remains at rest, it is indicative that no net force acts upon it.

The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.

This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).

At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.

Thus, statements A) and B) are true.

serg [1.1K]2 days ago
4 0

Answer:

The bonded molecules in the object are pushed upwards by the bonded molecules in the ground, matching the gravitational force pulling down on the object.

The ground exerts a normal force upwards on the object, equal to the gravitational force acting downwards on it.

Explanation:

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The total resistance in this circuit is (3Ω + 6Ω )  =  9Ω

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6 days ago
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Answer:

The resulting value is E_i = 1.5596 *10^{-18} \ J.

Explanation:

The question specifies that

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12 days ago
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serg [1198]

Answer:

20.353125 V

Explanation:

m = Mass of proton = 1.67\times 10^{-27}\ kg

q = Charge of proton = 1.6\times 10^{-19}\ C

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v_B = Velocity of proton at point B = 80 km/s

The relationship derived from energy conservation is as follows:

\dfrac{1}{2}m(v_B^2-v_A^2)=q(V_B-V_A)\\\Rightarrow V_B-V_A=\dfrac{1}{2q}m(v_B^2-v_A^2)\\\Rightarrow V_B-V_A=\dfrac{1}{2\times 1.6\times 10^{-19}}\times 1.67\times 10^{-27}(80000^2-50000^2)\\\Rightarrow V_B-V_A=20.353125\ V

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A 68 kg hiker walks at 5.0 km/h up a 9% slope. The indicated incline is the ratio of the vertical distance and the horizontal di
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</span>

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Force = Wy * g = W * sin θ * g

 

To find the angle θ, we utilize the slope, which is defined as:

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tan θ = 0.09

θ = 5.14˚

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</span>

<span>Now, let's compute the power:
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