Answer:
44.4m/s^2
Explanation:
Utilize the equation...S = ut + 1/2at^2
where...S = 32m...u = 0m/s....t = 1.20s
32 = (0)(1.20) + 0.5(1.20^2)a
; The acceleration due to gravity is 44.4m/s^2
The expected measurements should range as follows: 5, 10, 15, 20, and 25 meters.
Answer:
0.0031 m
Explanation:
y = Length of pixel = 281 μm
L = Distance to screen = 1.3 m
= Wavelength = 550 nm
d = Pupil diameter
= Angle
We have the expression

We have the expression

The pupil diameter calculates to 0.0031 m
There's an absence of circuit diagrams.
Initially, this causes worry for a moment, until we remember that we have no understanding of the experiment mentioned in the problem either, rendering such worries unnecessary.
Answer:
The horizontal distance d that the ball covers before it lands is 1.72 m.
Explanation:
Given,
Height of ramp 
Height of bottom of ramp 
Diameter = 0.17 m
We need to determine the horizontal distance d the ball travels before landing.
We need to calculate the time
Using the equation of motion




Next, we can find the ball's velocity
Using the kinetic energy formula



By applying the conservation of energy



We substitute the values into the equation


Next, we determine the horizontal distance d the ball travels before landing
Using the distance formula

Where. d = distance
t = time
v = velocity
We substitute the values into the formula


Thus, the horizontal distance d that the ball travels before it lands is 1.72 m.