answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grigory
9 days ago
10

So, why can a properly executed karate kick break a concrete block without fracturing bones [16]? first, bone is a very strong m

aterial. its ultimate compressive strength is approximately 40 times larger than concrete. second, contact is made with the edge of the foot. this concentrates the force into a small area of the target and reduces the likelihood of bending a bone to the point of fracture. third, the collision with the target is essentially inelastic and extends over several milliseconds, so the peak force, though large, does not exceed the strength of the bone. [8] george
b. benedek and felix m. h. villars, physics with illustrative examples from medicine and biology, vol. 1. (menlo park: addison-wesley publishing co., 1974). [16] s. r. wilk, r.
e. mcnair, and m. s. feld, am. j. phys. 51, 783 (1983). if a (cross-sectional area of the tibia) ~ 2.5 cm2


c


m


2


, compute how far a 67 kg person can fall and land stiff-legged on both legs without breaking a bone. assume f is split evenly between two legs. (hint: f≤2σ a


f


≤


2


σ


 


a


)
Physics
1 answer:
Yuliya22 [2.9K]9 days ago
3 0
Contact me for the complete response, if it’s not too late.
You might be interested in
The magnitude of the force associated with the gravitational field is constant and has a value FF . A particle is launched from
serg [3228]

Answer:

The particle's kinetic energy will equal 12U₀.

Explanation:

Given that,

A particle is fired from point B with an initial speed and arrives at point A with U₀ joules of kinetic energy gained.

The consistent force acting is 12F.

As per the problem,

The kinetic energy is

U_{0}=Fx....(I)

Constant force remains at 12F.

A resistive force field now exists,

With the resistive force defined as,

F_{r}=12F

As the particle travels from point B to point A,

We need to find the kinetic energy

Using the kinetic energy formula

U=F_{r}x

Substituting values for F_{r}

U=12Fx

Then, from equation (I)

U=12U_{0}

Consequently, the particle’s kinetic energy will amount to 12U₀.

7 0
1 month ago
Hawks and gannets soar above the ground and, when they spot prey, they fold their wings and essentially drop like a stone. They
Softa [2668]

Answer:

  v = 54.2 m/s

Explanation:

We can utilize conservation of energy to solve this issue.

Initial condition Higher

         Em₀ = U = m g h

Final condition. Lower

        Em_{f} = K = ½ m v²

        Em₀ = Em_{f}

        m g h = ½ m v²

         v² = 2gh

         v = √ (2gh)

Now let's perform the calculation

         v = √ (2 * 9.8 * 150)

         v = 54.2 m/s

3 0
1 month ago
A team of engineering students is testing their newly designed raft in the pool where the diving team practices.
Yuliya22 [2968]

Answer:

Lower than

Explanation:

When the cube is placed on the raft, the displaced water equals the combined weight of both the cube and raft. In contrast, when submerged in water, the displaced water corresponds to the raft's weight plus the cube's volume. Since the cube's volume is smaller than what is needed to displace its weight with water, the water level is lower.

6 0
1 month ago
A Honda Civic travels in a straight line along a road. The car’s distance x from a stop sign is given as a function of time t by
serg [3228]

a) Average velocity: 2.8 m/s

b) Average velocity: 5.2 m/s

c) Average velocity: 7.6 m/s

Explanation:

a)

The car's position over time t can be described by

x(t)=\alpha t^2 - \beta t^3

where

\alpha = 1.50 m/s^2

\beta = 0.05 m/s^3

To find the average velocity, we divide the displacement by the elapsed time:

v=\frac{\Delta x}{\Delta t}

At time t = 0, the position is:

x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0

At time t = 2.00 s, the position is:

x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m

This leads us to the displacement of

\Delta x = x(2)-x(0)=5.6-0=5.6 m

The duration for this interval is

\Delta t = 2.0 s - 0 s = 2.0 s

Therefore, the average velocity during this period is

v=\frac{5.6 m}{2.0 s}=2.8 m/s

b)

At time t = 0, the position is:

x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0

At time t = 4.00 s, the position is:

x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m

Thus, the displacement is

\Delta x = x(4)-x(0)=20.8-0=20.8 m

The time interval is

\Delta t = 4.0 - 0 = 4.0 s

This yields an average velocity of

v=\frac{20.8}{4.0}=5.2 m/s

c)

The position at t = 2 s is:

x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m

And at t = 4 s it is:

x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m

This gives us a displacement of

\Delta x = 20.8 - 5.6 = 15.2 m

While the time interval is

\Delta t = 4.0 - 2.0 = 2.0 s

So the resulting average velocity is

v=\frac{15.2}{2.0}=7.6 m/s

Find out more about average velocity:

6 0
1 month ago
An electron moves in a region where the magnetic field is uniform and has a magnitude of 80 μT. The electron follows a helical p
Softa [2668]

Answer:

3.4 x 10⁴ m/s

Explanation:

Analyze the circular path of the electron

B = magnetic field = 80 x 10⁻⁶ T

m = mass of an electron = 9.1 x 10⁻³¹ kg

v  = speed in the radial direction

r = radius of the circular trajectory = 2 mm = 0.002 m

q = charge of an electron = 1.6 x 10⁻¹⁹ C

For the electron’s circular movement

qBr = mv

(1.6 x 10⁻¹⁹) (80 x 10⁻⁶) (0.002) = (9.1 x 10⁻³¹) v

v = 2.8 x 10⁴ m/s

Now, consider the electron's movement in a straight line:

v' = speed in linear motion

x = distance traveled horizontally = 9 mm = 0.009 m

t = duration = \frac{2\pi m}{qB} = \frac{2\pi (9.1\times 10^{-31})}{(1.6\times 10^{^{-19}})(80\times 10^{-6})} = 4.5 x 10⁻⁷ sec

Using the formula

x = v' t

0.009 = v' (4.5 x 10⁻⁷)

v' = 20000 m/s

v' = 2 x 10⁴ m/s

The resultant speed is given by

V = sqrt(v² + v'²)

V = sqrt((2.8 x 10⁴)² + (2 x 10⁴)²)

v = 3.4 x 10⁴ m/s

6 0
25 days ago
Other questions:
  • A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the
    5·2 answers
  • A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
    10·1 answer
  • You do 174 J of work while pulling your sister back on a swing, whose chain is 5.10 m long, until the swing makes an angle of 32
    8·1 answer
  • An electric motor has a rating of 4.0 x 10^2 watts. How much time will it take for this motor to lift a 50.-kilogram mass a vert
    7·1 answer
  • In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r
    10·1 answer
  • A bus took 8 hours to travel 639 km. For the first 5 hours, it
    5·1 answer
  • A person travels distance πR along the circumference
    6·2 answers
  • Find the net electric force that the two charges would exert on an electron placed at point on the xx-axis at xx = 0.200 mm. Exp
    15·1 answer
  • Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m
    11·2 answers
  • A motorist inflates the tires of her car to a pressure of 180 kPa on a day when the temperature is -8.0° C. When she arrives at
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!