Response:
(a) 
(b) 
Clarification:
Greetings.
(a) In this case, since the starting volume is 18.5 dm³ and the ending volume is 21 dm³ (18.5 +2.5), we can calculate the work at constant pressure as shown below:

This value is negative as it expands against the given pressure.
(b) Furthermore, if the process is conducted reversibly, the pressure might change, hence, we need to calculate the work using:

The moles are calculated based on the provided mass of argon:

Consequently, the work amounts to:

Best regards.
if you want the short reply, the answer is B