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Schach
4 days ago
14

A 4.5-m-long wooden board with a 24-kg mass is supported in two places. One support is directly under the center of the board, a

nd the other is at one end. What can be said about the forces exerted by the supports?

Physics
2 answers:
Ostrovityanka [2.2K]4 days ago
8 0

All the weight of the wooden board rests solely on the support situated at the center of the rod, while the other support positioned at one end experiences no reaction force, resulting in a 0 reaction force.

Thus, the reaction force at the central support corresponds to the weight of the board, whereas the end support has 0 reaction force.

inna [2.2K]4 days ago
4 0

Answer:

The force applied by the support at the board's center pushes upward and matches the board's weight, which is mg ( 24x9.81)N, totaling 235.44N.

At the opposite end, the support does not contribute any force since the board is already stabilized by the central support.

Explanation:

An elaborate explanation and calculation can be found in the image below

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Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the
Yuliya22 [2438]

Response:

The acceleration of car 2 is four times that of car 1.

Rationale:

Centripetal acceleration occurs when an object travels in a circular route. It can be expressed as:

a=\dfrac{v^2}{r}

In this scenario, two race cars are moving at consistent speeds around a circular course. Both automobiles are located at an equal distance from the center, but car 2 is operating at twice the speed of car 1.

Thus,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{v_2^2}

1 and 2 represent the first and second cars, respectively.

v_2=2v_1

Consequently,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{(2v_1)^2}\\\\\dfrac{a_1}{a_2}=\dfrac{v_1^2}{4v_1^2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{4}\\\\a_2=4\times a_1

Therefore, car 2's acceleration is four times that of car 1.

4 0
18 days ago
Which, if any, of the following statements concerning the work done by a conservative force is NOT true? All of these statements
Yuliya22 [2438]

Answer:

If the starting and ending points are identical, the overall work equals zero.

Explanation:

Option (D) is correct.

A force is considered conservative when the work performed by it while moving an object from point A to point B does not rely on the path taken and remains consistent across all paths. The work done is determined solely by the initial and final locations of the particle. Thus, when the initial and final positions in a conservative field coincide, the work is said to be zero.

8 0
1 month ago
State two advantages of a lead-acid accumulator over a leclanche cell​
kicyunya [2264]

Respuesta:

Se pueden recargar.

Poseen una vida útil mayor.

Son reutilizables.

Explicación:

Las baterías de plomo-ácido y las pilas Leclanché son tipos de células electroquímicas.

Las pilas Leclanché son células primarias. Estas células producen reacciones químicas que generan corriente eléctrica de manera irreversible.

Por su parte, las baterías de plomo-ácido son células secundarias que permiten la reversibilidad de la corriente eléctrica generada.

Esto hace que las baterías de plomo-ácido sean reutilizables, con mayor durabilidad y un tiempo de vida más prolongado.

5 0
1 month ago
Compressed air is used to fire a 60 g ball vertically upward from a 0.70-m-tall tube. The air exerts an upward force of 3.0 N on
Yuliya22 [2438]

Answer:

2.87 m

Explanation:

Given parameters:

Mass of the ball (m) = 60 g = 0.06 kg

Height of the tube (h) = 0.70 m

Force applied on the ball by compressed air (F) = 3.0 N

Initial velocity of the ball (u) = 0 m/s (Assumed)

Final velocity of the ball at the tube's exit (v) =?

Acceleration of the ball (a) =?

The ball's weight is derived from multiplying mass and gravity. Therefore,

Weight (W) = mg=0.06\times 9.8=0.588\ N

Thus, the total force acting on the ball equals the net of upward force minus the weight.

Net force = Air force - Weight

F_{net}=F-mg\\F_{net}=3.0-0.588 = 2.412\ N

According to Newton's second law, net force equals the mass multiplied by acceleration.

F_{net}=ma\\\\a=\frac{F_{net}}{m}=\frac{2.412\ N}{0.06\ kg}=40.2\ m/s^2

Acceleration (a) is calculated as 40.2 m/s².

Using the motion equation, we find:

v^2=u^2+2ah\\\\v^2=0+2\times 40.2\times 0.7\\\\v=\sqrt{56.28}=7.5\ m/s

Let’s denote the maximum height achieved as 'H'.

Next, we apply the principle of energy conservation from the pipe's peak to the maximum height.

A decrease in kinetic energy equals an increase in potential energy.

\frac{1}{2}mv^2=mgH\\\\H=\frac{v^2}{2g}

Substituting the values, we solve for 'H', yielding:

H=\frac{56.28}{2\times 9.8}\\\\H=\frac{56.28}{19.6}=2.87\ m

Hence, the ball ascends to a height of 2.87 m above the top of the tube.

6 0
24 days ago
Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling backward with a
ValentinkaMS [2425]

Conclusion:

The total net force acting on the objects is 16 N, directed towards the right.

Clarification:

It is stated that,

The force exerted by the dog, F_1 = 32\ N (to the right)

The force exerted by Simone, F_2 = -16\ N (backward)

Here, assume the backward direction is negative and the right direction is positive.

The net force will move in the direction where the larger force is present. The net force can be calculated as:

F=F_1+F_2

F=32+(-16)

F = 16 N

Thus, the net force amounts to 16 N, acting towards the right.

6 0
24 days ago
Read 2 more answers
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