At a carnival, Andrew went on rides and played games.

A truck is carrying 10 3 bushels of apples, 10 2 bushels of grapes, and 10 1 bushels of oranges. Each bushel of apples weighs

Svet_ta [12734]

Answer:

10,088 pounds

Step-by-step explanation:

Provided data

103 bushels of apples

102 bushels of grapes

101 bushels of oranges

With the respective weight per bushel:

Apples = 32 pounds

Grapes = 25 pounds

Oranges = 42 pounds

The total weight can be calculated by summing the products of each type:

Total Weight: 103(32) + 102(25) + 101(42) = 10,088 pounds

5 0

2 months ago

19. The population of Jose's town in 1995 was 2400 and the population in 2000 was

Inessa [12570]

The linear equation in slope-intercept format representing the population of Jose's town is y = 320x + 2400. The town's population in 1995 was recorded at 2400, increasing to 4000 by 2000. By establishing x as the number of years since 1995, we derive the linear equation from the change in population per year.

5 0

1 month ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Employee Number

Zina [12379]

The average years of employment is 14

with 73% having worked for at least 10 years.

To find the mean, add up the years of service and divide by the number of employees. The total years worked is 417, so the formula yields:

average years worked = 417/30 = 13.9, rounded to approximately 14 years.

To determine the percentage of employees with ten or more years, count those with 10 or more years and divide by the total employee count, converting the result into a percentage:

(10 years or over)/(total number) = 22/30 = 0.73 repeating, which approximates to 73%.

Using a spreadsheet tool can make this calculation simpler, as it can quickly compute the average and help tally how many employees have worked for 10 years or more.

3 0

1 month ago

Read 2 more answers

Which shapes have the same volume as the given rectangular prism?<br><br>base area = 50 cm^2

PIT_PIT [12445]

The initial shape.

5 0

1 month ago

The time for a visitor to read health instructions on a Web site is approximately normally distributed with a mean of 10 minutes

Svet_ta [12734]

Response:

a) The average is 10 and the variance is 0.0625.

b) 0.6826 = 68.26% likelihood that the average time of visitors falls within 15 seconds of 10 minutes.

c) 10.58 minutes.

Step-by-step clarification:

To figure this out, we must comprehend the normal probability distribution alongside the central limit theorem.

Normal Probability Distribution

Issues involving normal distributions can be resolved using the z-score formula.

For a data set with mean $\mu$ and standard deviation $\sigma$ , the z-score related to a measure X is defined as:

$Z = \frac{X - \mu}{\sigma}$

The z-score illustrates how many standard deviations the measure is positioned from the mean. Once the z-score is calculated, we refer to the z-score table to find the p-value matching this z-score. This p-value reflects the likelihood that the measurement is less than X, which means it indicates the percentile of X. To determine the chance that the measure exceeds X, we subtract the p-value from 1.

Central Limit Theorem

The Central Limit Theorem states that for a normally distributed random variable X, defined by mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of sample means of size n can be approximated as a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For non-normal distributions, this theorem applies if n is at least 30.

In this case, the distribution has a mean of 10 minutes and a standard deviation of 2 minutes.

This indicates that $\mu = 10, \sigma = 2$

Assuming 64 visitors independently access the site.

This implies that $n = 64, = \frac{2}{\sqrt{64}} = 0.25$

a. The expected value and variance of the average time of the visitors.

Employing the Central Limit Theorem, the mean is 10 and the variance is (0.25)^2 = 0.0625.

b. The chance that the mean visit duration is within 15 seconds of 10 minutes.

15 seconds = 15/60 = 0.25 minutes, thus between 9.75 and 10.25 seconds, which corresponds to the p-value of z when X = 10.25 minus the p-value of z when X = 9.75.

X = 10.25

$Z = \frac{X - \mu}{\sigma}$

Through the Central Limit Theorem

$Z = \frac{X - \mu}{s}$