6. It is now 10:29 a.m., but when the bell rings at 10:30 a.m. Suzette will be late for French class for the third time this wee

Question

1 month ago

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6. It is now 10:29 a.m., but when the bell rings at 10:30 a.m. Suzette will be late for French class for the third time this wee

k. She must get from one side of the school to the other by hurrying down three different hallways. She runs down the first hallway, a distance of 35.0 m, at a speed of 3.50 m/s. The second hallway is filled with students, and she covers its 48.0 m length at an average speed of 1.20 m/s. The final hallway is empty, and Suzette sprints its 60.0 m length at a speed of 5.00 m/s.
a. Does Suzette make it to class on time or does she get detention for being late again?
b. Draw a distance vs. time graph of the situation. (Assume constant speeds for each hallway.)

Mathematics

2 answers:

lawyer [12.5K] · Answer 1 · 2026-02-20T06:54:13+03:00

lawyer [12.5K]1 month ago

8 0

Step-by-step explanation:

I hope this is useful to you

Please consider marking my response as brainalist

Zina [12.3K] · Answer 2 · 2026-02-20T06:54:36+03:00

Zina [12.3K]1 month ago

4 0

Answer:

Check the attached document for the calculations. $\Huge {\uparrow}$

Thus, Sujata arrives 2 seconds late.

Graph:-

$\setlength{\unitlength}{2.5mm}\begin{picture}(10,10)\linethickness{0.45mm}\put(20,20){\vector(1,0){18}}\put(20,20){\vector(-1,0){18}}\put(20,20){\vector(0,1){18}}\put(20,20){\vector(0,-1){18}}\multiput(19.35,6)(0,2){15}{\line(1,0){1.3}}\multiput(6,19.35)(2,0){15}{\line(0,1){1.3}}\put(20,20){\circle*{1}}\qbezier(20,20)(25,21)(27,36)\qbezier(20,20)(15,22)(13,36)\end{picture}$