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diamong
3 months ago
10

On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above

and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1
Mathematics
2 answers:
Inessa [12.5K]3 months ago
8 0

Answer:

y\geq\frac{1}{3}x-1

Step-by-step explanation:

A solid straight line with a positive slope passes through points (0, -1) and (3, 0).

Determine the slope of the solid line.

m=(0+1)/(3-0)\\\\m=\frac{1}{3}

The equation in slope-intercept format for the solid line is

y=mx+b

we have

m=\frac{1}{3}

b=-1 ---> the problem presented

insert values

y=\frac{1}{3}x-1

The area above and to the left of the line is shaded.

Thus, the corresponding inequality is

y\geq\frac{1}{3}x-1

AnnZ [12.3K]3 months ago
5 0

Answer:

Step-by-step explanation:

It's B; I just completed the quiz.

y ≥ One-thirdx − 1

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