Response:
A 2:3
Detailed Explanation:
10:15
which is equivalent to 10/15
which simplifies to 2/3
I hope this assists you
<3
Red
Answer:

Step-by-step explanation:
The initial scenario is a specific case of the subsequent one, so we will address the second case first.
Consider
. Through the utilization of derivatives and trigonometric function properties, it is determined that


The equation is represented as
. It's important to note that since
it leads to the equation
,
which signifies that
. Consequently, 
It's notable that in this instance, the value of k is independent of A and B. Thus, it applies universally to any values of A and B. The first scenario is included since it corresponds to A=0 and B=1.
To determine the variance, we need to first calculate the second moment as follows: The variance can be determined using this equation: The standard deviation is simply the square root of the variance, which gives us the result.
Answer: OPTION B
Step-by-step explanation:
The red graph depicts the fundamental form of a quadratic function (the most basic version), with its vertex located at the origin.
The function g(x) results from moving the parent function 2 units to the right and 1 unit upwards.
As a consequence, considering this, the transformation takes the following structure:

The horizontal displacement is dictated by the value of h, while the vertical shift is determined by k.
<pThus, the resulting function is:

Answer:
At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.
Step-by-step explanation:
A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.
The null and alternative hypotheses are:

The significance level is set at 0.10.
The sample mean recorded is 17, and the sample standard deviation is 5.37.
The degrees of freedom are calculated as df=(20-1)=19.
The t-statistic is:

The two-tailed P-value corresponding to t=1.67 is P=0.11132.
<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.
At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.