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jarptica
1 month ago
13

Which of the following are dimensionally consistent? (Choose all that apply.)(a) a=v / t+xv2 / 2(b) x=3vt(c) xa2=x2v / t4(d) x=v

t+vt2 / 2(e) v=x2 / at3(f) a3=x2v / t5(g) x=t(h) v=5at

Mathematics
1 answer:
lawyer [12.5K]1 month ago
8 0
The consistency of the dimensions is identified as follows: A: dimensionally consistent B: not dimensionally consistent C: dimensionally consistent D: not dimensionally consistent E: not dimensionally consistent F: dimensionally consistent G: dimensionally consistent H: not dimensionally consistent In dimensional analysis, we represent: Length as L, Time as T, Mass as M.
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Machines at a factory produce circular washers with a specified diameter. The quality control manager at the factory periodicall
zzz [12365]

Answer:

A Type I error could occur if the test shows that the proportion is above 90%, while in reality, the actual proportion is 90%.

Step-by-step explanation:

Machines in a factory produce circular washers that meet a specific diameter.

The quality control manager routinely assesses samples of washers to ensure that more than 90% conform to the specified diameter.

Let p represent the proportion of washers that meet the specified diameter

Thus, Null hypothesis: p = 90% H_0

Alternative Hypothesis: p > 90%H_A

Here, the null hypothesis posits that the proportion is exactly 90%. In contrast, the alternative hypothesis suggests that the proportion exceeds 90%.

Now, a Type I error indicates the probability of rejecting the null hypothesis while it is actually true or, in simple terms, the likelihood of incorrectly rejecting a valid hypothesis.

Thus, based on our question, a Type I error would declare that the test convincingly indicates the proportion is over 90%, while in truth, it remains 90%.

0 0
2 months ago
The perimeter of a △ABC equals 12 in. The midpoints of the sides M, N and K are connected consecutively. Find the perimeter of △
Zina [12379]
You can easily calculate the result for each segment and then sum them to determine the perimeter of triangle MNK.
8 0
1 month ago
Read 2 more answers
What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
Inessa [12570]

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format y/x=k or y=kx

For this question, we have

the point (5,12) lies on the direct variation line

therefore

Determine the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

The equation is

y=\frac{12}{5}x

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point (0,0)

x=0\ y=0

Insert the values of x and y into the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is valid

thus

the point (0,0) lies on the direct variation line

case B) point (2.5,6)

x=2.5\ y=6

Insert the values of x and y into the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is valid

thus

the point (2.5,6) lies on the direct variation line

case C) point (3,10)

x=3\ y=10

Insert the values of x and y into the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not valid

thus

the point (3,10) does not lie on the direct variation line

case D) point (7.5,18)

x=7.5\ y=18

Insert the values of x and y into the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is valid

thus

the point (7.5,18) lies on the direct variation line

case E) point (12.5,24)

x=12.5\ y=24

Insert the values of x and y into the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not valid

thus

the point (12.5,24) does not lie on the direct variation line

case F) point (15,36)

x=15\ y=36

Insert the values of x and y into the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is valid

thus

the point (15,36) lies on the direct variation line

ultimately

the solution is

(0,0)

(2.5,6)

(7.5,18)

(15,36)


5 0
3 months ago
Read 2 more answers
Examine the equation.
AnnZ [12381]
The least common denominator needed to combine the variable terms is 15. The least common denominator for the constant terms is 21.
8 0
2 months ago
Read 2 more answers
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