Response:
a. 55 cars
b. 25 cars
Detailed explanation:
Let’s denote the quantity of cars with stereo systems as N(ss), those with air conditioning as N(ac), and those with sunroofs as N(sr).
We find that:
N(ss) = 30
N(ac) = 30
N(sr) = 40
N(ss and ac and sr) = 15
N(at least two) = 30
a.
To calculate how many cars possess at least one feature (N(at least one) or N(ss or ac or sr)), we apply:
N(ss or ac or sr) = N(ss) + N(ac) + N(sr) - N(ss and ac) - N(ss and sr) - N(ac and sr) + N(ss and ac and sr)
N(ss or ac or sr) = 30 + 30 + 40 - (N(at least two) + 2*N(ss and ac and sr)) + 15
Substituting, we find N(ss or ac or sr) = 30 + 30 + 40 - (30 + 2*15) + 15 = 55
b.
For those cars that have exactly one feature, we have:
N(only one) = N(at least one) - N(at least two)
N(only one) = 55 - 30 = 25
Answer:
1. 8.4 2. 15
Step-by-step explanation:
1. 4x + 8y = 40
when y = 0.8
4x + 8 × 0.8 = 40
4x = 40 - 8 × 0.8
4x = 40 - 6.4 = 33.6
....x = 33.6 / 4 = 8.4
2. 3a + b = 54
when b = 9
3a + 9 = 54
3a = 54 - 9
3a = 45
.....a = 45 / 3 = 15
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The provided values are
$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155
To start, we will arrange these in ascending order
resulting in
$60 $85 $95 $105 $120 $145 $155 $175 $190 $215 $235 $240 $260 $285 $315
The total count is 15
the position of 105 is 4
Now, we can calculate the percentile

Thus, the percentile for the bid of $105 is 26.667%...........Response
70%Step-by-step explanation:First, determine how many fixtures are left to install.270-81=189. The fraction representing the work still to be done is the count of fixtures to install divided by the total amount. So, % of work remaining equals 189 divided by 270, which equals 0.7. Converting this to percentage form gives us 0.7 * 100% = 70%.
You have two kinds of data $ and %!
Align them properly and perform cross multiplication.
16% corresponds to $38 as
100% corresponds to $x
Following this, x = (38*100)/16 = $237.5, which is the original price before the discount.