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Paladinen
1 month ago
6

Tom and jerry have to stuff and seal 63 envelopes for a new marketing campaign. Jerry can stuff and seal 15 envelopes alone in 2

minutes. Tom can do 3 envelopes per minute. Enter the equation that can be used to find the number of minutes t. It takes Tom and Jerry to stuff and seal 63 envelopes
Mathematics
1 answer:
Zina [12.3K]1 month ago
7 0
Chile—. I understand, best of luck anyway.....
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If p+pq is 4 times p-pq, and pq does not equal to 0, which of the following has exactly one possible value? A)p B)q C)pq D)p+pq
Inessa [12570]
D is the correct option since it represents a combination where neither p nor a equals zero.
8 0
1 month ago
The calculation needed to find the cost of the factory tour was $5(29 students). Melissa used the expression $5(20 + 9). Mrs. Ga
AnnZ [12381]
Honestly, I find Mrs. Garcia's method easier to perform mentally. It hinges on how familiar you are with your multiples of 5. (5*15 = 75 is a multiplication I often use)

Melissa's approach involves calculating 5*20 = 100 and 5*9 = 45, then combines the 3-digit result 100 with the 2-digit result 45, yielding 145. Adding 45 to 00 is simple and doesn’t require carrying digits, thus the arithmetic is fairly straightforward.

Mrs. Garcia's technique involves computing 5*14 = 70 and 5*15 = 75, then summing these two-digit results. Many people may not readily recall that 5*15=75, which complicates forming that product. The addition of 70 and 75 requires a carrying operation, making the math somewhat more complex. The resulting total is 145.

(The rationale behind my preference for Mrs. Garcia's method is that I can achieve the final sum by simply doubling 7 tens, followed by adding 5. The only 3-digit number to remember mentally is the ultimate total.)

_____Subtraction introduces a slight complication, yet reshaping it as $5(30 -1) = $150 - 5 = $145 is possible.
Or, you may reframe it as $5(28 +1) = $140 +5 = $145.
Dividing an even number by 2 to find the product of 5 is straightforward when you append a zero.
  5*14 = 10*7 = 70
  5*28 = 10*14 = 140.
7 0
23 days ago
Read 2 more answers
To investigate whether or not sexism was present in the workplace, 48 male bank supervisors were each given a personnel file and
AnnZ [12381]
There is clear favoritism present. However, it is crucial to examine not just how many women were promoted in comparison to men but also the rate of promotion within each group. In the case of men, 21 out of 24 received promotions, indicating a substantial rate of 87.5%. In contrast, for women, only 14 out of 24 were promoted, which is 58.3%, just over half. Therefore, we can conclude that there is a distinct bias favoring male employees.
6 0
14 days ago
The domain of f(x) is the set of all real values except 7, and the domain of g(x) is the set of all real values except –3. Which
Svet_ta [12734]

Answer: All real numbers except for x ≠ 7 and those x for which f(x)≠-3

Step-by-step explanation:

The domain of function f is defined as R - {7}

In other words, if x belongs to the domain of f,

then, x cannot equal 7

(gof)(x) = g(f(x))

Considering that g has a domain of R - {-3}

Therefore, if f(x) fits within the domain of g,

it follows that f(x)≠ -3

Consequently, the fourth option is the right choice.

8 0
26 days ago
A rectangle has area 25 m2. express the perimeter of the rectangle as a function of the length l of one of its sides. p(l) = sta
zzz [12365]
a) The area of a rectangle is calculated by multiplying the length by the width:
   A = l·w

This formula allows us to express the width in terms of area and length. By dividing A by l, we find
   A/l = w

We also recognize that the perimeter of a rectangle is the total length around it.
   P = l + w + l + w
   P = 2(l + w)
We aim to rewrite the perimeter formula to isolate l on one side, using the expression for w derived earlier.
   P = 2(l + A/l)

By substituting the known value for A, we can express p(l) as
   p(l) = 2(l + 25/l)
   p(l) = 2l + 50/l


b)
For lengths exceeding widths, we have
   l > w
   l > A/l
   l² > A
   l > √A
   l > √25

This indicates that the domain of p(l) is
   l ∈ (5, ∞)..... meters
4 0
1 month ago
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