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Sonbull
1 month ago
6

In a certain sequence of all positive terms, {a1, a2, a3, …} each term equals the previous term times a constant factor. If (a1)

(a5) = 900, what is the value of a3?
Mathematics
1 answer:
babunello [11.8K]1 month ago
7 0

Let k represent the constant multiplier between successive terms, which allows us to express

a_2=ka_1

a_3=ka_2=k^2a_1

and so forth, given that

a_n=ka_{n-1}=\cdots=k^{n-1}a_1

(observe that the sum of the exponent and the subscript equals n)

Thus

a_5=k^4a_1

implying that if

a_1a_5=900

then

k^4{a_1}^2=900\implies k^4=\dfrac{900}{{a_1}^2}=\left(\dfrac{30}{a_1}\right)^2\implies k^2=\dfrac{30}{a_1}

At this point,

a_3=k^2a_1=\dfrac{30a_1}{a_1}=30

therefore the third term in the series is 30.

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Answer:

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Refer to the attached image for the plot.

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