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Sonbull
9 days ago
6

In a certain sequence of all positive terms, {a1, a2, a3, …} each term equals the previous term times a constant factor. If (a1)

(a5) = 900, what is the value of a3?
Mathematics
1 answer:
babunello [11.8K]9 days ago
7 0

Let k represent the constant multiplier between successive terms, which allows us to express

a_2=ka_1

a_3=ka_2=k^2a_1

and so forth, given that

a_n=ka_{n-1}=\cdots=k^{n-1}a_1

(observe that the sum of the exponent and the subscript equals n)

Thus

a_5=k^4a_1

implying that if

a_1a_5=900

then

k^4{a_1}^2=900\implies k^4=\dfrac{900}{{a_1}^2}=\left(\dfrac{30}{a_1}\right)^2\implies k^2=\dfrac{30}{a_1}

At this point,

a_3=k^2a_1=\dfrac{30a_1}{a_1}=30

therefore the third term in the series is 30.

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What is a31 of the arithmetic sequence for which a5=3.2 and a9=12.0?
zzz [12365]

The formula for an arithmetic sequence:

a_n=a_1+(n-1)d

We are given:

a_5=3.2,\ a_9=12.0

Determine d (the common difference)

a_9-a_5=4d\\\\4d=12.0-3.2\\\\4d=8.8\ \ \ |:4\\\\d=2.2

Calculate a31:

a_{31}=a_5+26d\\\\a_{31}=3.2+26\cdot2.2=60.4

7 0
1 month ago
Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [12383]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
1 month ago
Set G is the set of positive integers divisible by 4 in set if is the set of perfect squares list the first five elements of set
Inessa [12570]
Set G consists of: G={4, 8, 12, 16, 20, 24, 28, 32, 36,...} Set F represents the perfect squares: F={1, 4, 9, 16, 25, 36, 49, 64, 81, 100...} Within set F, the numbers 4, 16, 36, 64, and 100 are multiples of 4. The result is: {4, 16, 36, 64, 100}.
5 0
1 month ago
If f(x) = − 5, what is f(8.6)?
zzz [12365]
8.6 = -5
13.6 = 0
Your equation seems to be lacking another value for x, but based on what you've provided, this is accurate.
5 0
23 days ago
Read 2 more answers
Robby had 4 4/9 bags of pet food.All of the bags held the same amount of food when they were full.Of Robby's 4 4/9 bags of pet f
Zina [12379]

Respuesta: 1.8 bolsas

Explicación paso a paso:

A partir de la pregunta, considerando que Robby tiene 4 4/9 bolsas de comida para mascotas, 2/5 eran comida para perros.

2/5 de 4 4/9 = comida para perros.

Convierte 4 4/9 a fracción impropia= 40/9.

2/5 de 40/9 implica 2/5 × 40/9.

= 16/9.

= 1.78 o 1.8.

Espero que esto sea útil, por favor marca como la mejor respuesta.

4 0
1 month ago
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