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1 month ago

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The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 × 106 Btu/h. The comb

ustion efficiency of the boiler is measured to be 0.7 by a hand-held flue gas analyzer. After tuning up the boiler, the combustion efficiency rises to 0.8. The boiler operates 5200 h a year intermittently. Taking the unit cost of energy to be $23/106 Btu, determine the annual energy and cost savings as a result of tuning up the boiler.

1 answer:

marusya05 [3K]1 month ago

4 0

Solution:

Given Information,

Heat input = ( $Q_{in}$ ) = 5.5 × $10^{6}$ Btu/h

Efficiency of combustion for the boiler ( $n_{furnance}$ ) = 0.7

Efficiency after adjustments ( $n_{furnance,now}$ ) = 0.8

Operating Hours (t) = 5200h

Unit cost (c) = $\frac{23 dollar}{10^{6}Btu }$

Calculate heat output from the boiler $Q_{out}$ = $Q_{in}$ x $n_{furnance}$

= 5.5 x $10^{6}$ x 0.7

= 3.85 x $10^{6}$ Btu/h

Now determine the heat input after the upgrade

$(Q_{in} ){new}$ = $Q_{out}$ / $(n_{furnance} ){new}$

= 3.85 x $10^{6}$ / 0.8

= 4.8125 x $10^{6}$ Btu/h

Calculate the energy conserved post-tuning

$(Q_{in} ){saved}$ = $Q_{in}$ - $(Q_{in} ){new}$

= 5.5 x $10^{6}$ - 4.8125 x $10^{6}$ Btu/h

= 0.6875 x $10^{6}$ Btu/h

Calculate the yearly energy savings ( $E_{Saving}$ )

$E_{Saving}$ = $(Q_{in} ){saved}$ x t

= ( 0.6875 x $10^{6}$ Btu/h ) ( 5200 hr/yr)

= 3575 x $10^{6}$ Btu/h

Lastly, calculate the annual cost savings

Annual savings = $E_{Annual saving}$ x Unit cost

= 3575 x $10^{6}$ Btu/h x $\frac{23 dollar}{10^{6}Btu }$

= 82225

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