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Anton
1 month ago
15

Limes are on sale. That sale price is 8 limes for $2.00. Why could the unit rate be 4 or 0.25?

Mathematics
1 answer:
babunello [11.8K]1 month ago
4 0

Answer:

C. No, since the price for each lime will be slightly above 30¢, meaning that purchasing 4 limes would result in a total cost that exceeds $1.20.Step-by-step explanation:

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Tran has a credit card with a spending limit of $2000 and an APR (annual percentage rate) of 12%. During the first month, Tran c
babunello [11817]

Detailed explanation:

Information provided:

Tran possesses a credit card that allows up to $2000 in spending with an APR of 12%.

In the initial month, Tran incurred charges of $450 and settled $150 within that billing period.

The formula to determine the interest that will accrue for Tran in the first month is (0.012)(300)

Here, 0.01 signifies the monthly interest rate.

The 300 reflects the outstanding balance, as Tran charged $450 but only paid back $150.

5 0
1 month ago
A rocket was launched into the air from a podium 6 feet off the ground. The rocket path is represented by the equation h(t)=-16t
lawyer [12517]

Answer:

60

Step-by-step explanation:

The function provided is:

h(t)=-16t^2+120t+6

The average rate of change of h(t) as time goes from t=a to t=b is expressed as:

\frac{h(b)-h(a)}{b-a}

This function can be reformulated as: h(t)=-16(t-3.75)^2+231

The rocket's peak height is 231, which occurs at t=3.75 seconds.

\implies h(3.75)=231

The initial launch happens at: t=0

and h(0)=-16(0)^2+120(0)+6=6

The average rate of change from launch to max height is

\frac{h(3.75)-h(0)}{3.75-0}=\frac{231-6}{3.75-0} =60

6 0
1 month ago
Question Number 12 You are a landscaper working on the design of a parking lot in a new shopping center. You are measuring the l
babunello [11817]

Answer:

Length\: of\: D=37\frac{3}{16} \:feet

Step-by-step explanation:

Here are the details provided:

  • The handicapped space measures 10\frac{1}{16} feet next to the curb.
  • The other three spaces each are 8\frac{3}{8} feet wide.
  • There are four lines separating the spaces, each line being \frac{1}{2} foot long.

The Median D will be calculated as follows:

  • Width of the handicapped spot
  • 3 times the width of the other spaces
  • 4 times the width of the lines

= 10\frac{1}{16} + (3 X 8\frac{3}{8})+(4 X\frac{1}{2})\\=\frac{161}{16} + \frac{3 X 67}{8}+\frac{4}{2}\\=\frac{161}{16} + \frac{201}{8}+\frac{4}{2}\\=\frac{161+402+32}{16}\\=\frac{595}{16}\\Length\: of\: D=37\frac{3}{16} \:feet

7 0
1 month ago
Use the alternative curvature formula K=|a x v|/|v|^3 to find the curvature of the following parameterized curves.
PIT_PIT [12445]

Answer:

K=\frac{2}{(4t^{2}+1)^{\frac{3}{2}}}

Step-by-step explanation:

First, we determine v and a as:

v(t)=\frac{dr(t)}{dt}=(2t,1,0)

a(t)=\frac{dv(t)}{dt}=(2,0,0)

Subsequently, we compute the cross product and substitute it into the formula for k

a(t) X v(t) = (0,0,2)

| a(t) X v(t) | = 2

| v |^{3} = (4t^{2}+1)^{\frac{3}{2}}

Thus, we conclude

K=\frac{2}{(4t^{2}+1)^{\frac{3}{2}}}

I trust this is of assistance to you

best regards

8 0
11 days ago
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40
lawyer [12517]

Response:

0.14 s

Detailed breakdown:

s = -2.7 t² + 40t + 6.5

Set s = 12

12 = -2.7t² + 40t + 6.5     Rearranging yields

-2.7t² + 40t + 6.5 - 12 = 0

      -2.7t² + 40t - 5.5 = 0

Utilize the quadratic formula

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = -2.7; b = 40; c = -5.5

x = \frac{-40\pm\sqrt{40^2 - 4\times (-2.7) \times (-5.5)}} {2(-2.7)}

x = \frac{-40\pm\sqrt{1600-59.4}}{-5.4}

x = \frac{-40\pm\sqrt{1540.6}}{-5.4}

x = \frac{-40\pm 39.25}{-5.4}

x = 7.41 ± 7.27

x₁ = 0.14; x₂ = 14.68

The graph indicates roots at x₁ = 0.134 and x₂ = 14.68.

The surface of the Moon stands at -12 ft. Thus, the ball will reach a height of 12 ft above the Moon’s surface (crossing the x-axis) at 0.14 s.

The second root indicates when the ball is again 12 ft above the lunar surface as it descends.

6 0
1 month ago
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