They intersect at right angles, which defines perpendicular lines.
The correct answer is perpendicular based on the concept of Parallel and Perpendicular lines from Khan Academy.
The question appears to be incomplete. Here’s the complete inquiry:
Samir is quite skilled with the gun. When he targets a specific aim at the shooting range, he has a 0.95 probability of striking it. On one occasion, Samir sets out to shoot 10 targets consecutively.
If he has the same chance of hitting each of the 10 targets, what is the likelihood that he will miss at least one?
Response:
40.13%
Step-by-step breakdown:
Let 'A' represent the event of successfully hitting all targets in 10 trials.
The complement of 'A' is 
Now, since Samir has a consistent probability of hitting each target at 0.95.
Now, 
We know that the combined probability of an event and its complement equals 1.
<pThus,

Consequently, the probability that he misses at least one target among 10 attempts is 40.13%.
We determine that the true average calorie content as estimated in the sampled population surpasses the actual calorie content. Step-by-step explanation: An article discussed a pilot study where each of the 58 participants was asked to estimate the calorie count of a 12 oz beer known to have 153 calories. The observed sample mean of calorie estimation was 193, with a sample standard deviation of 88. Let

=
true average estimated calorie level within the sampled population. Thus, Null Hypothesis, :
153 calories {indicating that the true average estimated calorie content does not exceed the actual amount}. Alternative Hypothesis,
:
> 153 calories {indicating the true average estimation exceeds the actual}. The appropriate test statistic would be a one-sample t-test statistic, as we lack knowledge of the population standard deviation; Test Statistic = ~t = 
where, sample mean estimated calorie level = 193 calories, s = sample standard deviation = 88, and n = sample size = 58. Therefore, the test statistic = ~t = 3.462. The t-table indicates a critical value of 1.6725 for 57 degrees of freedom at a 0.05 significance level. Since our test statistic of 3.462 > 1.6725, we have sufficient evidence to reject the null hypothesis; thus, affirming that the true average estimated calorie content in the sampled population exceeds the real content.
Answer:
Option 2 50 ≤ s ≤ 100
Option 5 She can make a deposit of $50
Option 6 She can make a deposit of $75
Detailed explanation:
Let
s represent the amount of money Layla puts into her savings account.
We know that
25% = 25/100 = 0.25
50% = 50/100 = 0.50
Thus
-----> 
-----> 
The compound inequality is

Check each case
case 1) 25 ≤ s ≤ 50
This statement is false
Refer to the procedure
case 2) 50 ≤ s ≤ 100
This statement is true
Refer to the procedure
case 3) s ≤ 25 or s ≥ 50
This statement is false
Because s ≤ 100 and s ≥ 50
case 4) s ≤ 50 or s ≥ 100
This statement is false
Because s ≤ 100 and s ≥ 50
case 5) She can make a deposit of $50
This statement is true
As the value of s meets the compound inequality 
case 6) She can make a deposit of $75
This statement is true
As the value of s meets the compound inequality 