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docker41
14 days ago
5

Mr. Tan's rectangular swimming pool has an area of (81x2 - 144y2) square feet. What are the dimensions of his pool?

Mathematics
2 answers:
PIT_PIT [9.1K]14 days ago
8 0
Therefore, the dimensions of the pool can be expressed as (9x - 12y)(9x + 12y).
Leona [9.2K]14 days ago
5 0
Thus, the pool's dimensions are (9x + 12y) and (9x - 12y).
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A ship sails at 15 miles per hour, while it can motor at 5 miles per hour. It sails for 6 hours to its destination but has to mo
tester [8842]

Greetings!

The conclusion is:

The return trip will take 18 hours.

Reasoning:

To determine the duration of the return journey, we must calculate the distance from the destination back to the starting point.

The ship travels at 15 miles per hour (mph) over 6 hours, yielding a distance of:

x=x_o+v*t\\\\x=0+15mph*6hours=90miles

The distance from the starting point to the destination is 90 miles, and for the return trip, the motor operates at a speed of 5 mph. Thus, computing the time taken gives us:

Distance=v*t\\\\t=\frac{Distance}{v}=\frac{90miles}{5mph}=18hours

Consequently, the return trip will take 18 hours to complete.

Have a nice day!

5 0
3 days ago
Before the last school year began, it was estimated that the average discretionary personal expenses each school year for a stud
tester [8842]

Answer:

M=2,179.29

The average exceeds the estimate

Her expenses would need to be $1,625.00

Step-by-step explanation:

1.) What is the mean of her friends' personal expenses?

The mean is defined as the average expense value, calculated as follows:

M=\frac{2,800+1,990+2,005+2,400+1,860+2,200+2,000}{7}\\M=2,179.29

2.) Is the average higher or lower than the estimate?

Given the estimate of $2,110, the average is indeed higher than this estimate.

3.)What amount of personal expenses would Ashley need to maintain a combined average of $2,110 with her friends' amounts for that school year?

M= 2,110=\frac{7*2,179.29+x}{8} \\x=2,110*8 - 15,255\\x=1,625

Her needed amount of expenses would be $1,625.00.

4 0
3 days ago
An automobile manufacturer sold 30,000 new cars, one to each of 30,000 customers, in a certain year. The manufacturer was intere
babunello [8412]
A) To establish a sampling plan, follow these 5 steps:
    1) Identify the sample population: which customers will you reach out to?
       Those who purchased a new car during a specific year.
    2) Determine the population size: how many customers will you contact?
       From the 30,000 car buyers, select 1,000 customers to contact.
    3) Select contact method: what is your means of contacting customers?
       Since you have a list with names and addresses, mailing questionnaires is feasible.
    4) Define the sampling frame: what is the timeline or deadline for contacting customers?
       Send out questionnaires and allow two months for responses.
    5) Decide on the analysis approach: is your research qualitative or quantitative?
     You aim for quantitative research, so you will use probabilistic sampling.

B) The 32.5% probability relates only to those customers who experienced mechanical issues, specifically power door lock problems, and does not account for those without any problems or those reporting issues after the first 5,000 miles.

C) To estimate the probability of power door lock problems among all customers within the first 5,000 miles, consider the entire sample:
P = 13 / 1000 = 0.013

Therefore,
N = 0.013 × 30,000 = 390

Thus, the estimated number of new cars that had power door lock issues within 5,000 miles is 390.
         
4 0
1 month ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
babunello [8412]

Response:

the expected value of this raffle if you purchase 1 ticket = -0.65

Breakdown of the calculation:

Details:

5,000 tickets are sold at​ $1 each for a charitable raffle

Winners will be chosen at random with cash prizes as follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Therefore, the value and its respective probability can be calculated as follows:

Value                              Probability

$500 - $1 = $499              1/5000

$300 - $1 = $299              3/5000

$50 - $1 = $49                    5/5000

$5 - $1 = $4                     20/5000

-$1                           1 - 29/5000 = 4971/5000

The expected value of the raffle when buying 1 ticket is computed as follows:

E(x) = \sum x * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000} + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016 + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

So, the expected value of this raffle when one ticket is purchased = -0.65

7 0
7 days ago
The value of y at x=-1in the equation 5y=2 is
Zina [9171]

Answer: y = 2/5 --> y = 0.4

Step-by-step explanation:

The equation 5y = 2 represents a horizontal line at y = 2/5.

This means that the y-coordinate holds the value of 2/5 = 0.4 for any x-coordinate.

7 0
1 month ago
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